3 years ago

Using the quadratic formula, what is the value of x for x^2-4+5=0

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

4 0

value of x is: x= i and x= -i

Step-by-step explanation:

We need to find the value of x from $x^2-4+5=0$ using quadratic formula.

The term is: $x^2+1=0$

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

Where a = 1, b=0,c=1

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{0\pm\sqrt{(0)^2-4(1)(1)}}{2(1)}\\x=\frac{\pm\sqrt{-4}}{2}\\x=\frac{\pm2i}{2}\\x=\pm i$

So, value of x is: x= i and x= -i

Keywords: Quadratic formula

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