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Inessa05 [86]
4 years ago
11

Using the quadratic formula, what is the value of x for x^2-4+5=0​

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
4 0

value of x is: x= i and x= -i

Step-by-step explanation:

We need to find the value of x from x^2-4+5=0​ using quadratic formula.

The term is: x^2+1=0​

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\

Where a = 1, b=0,c=1

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{0\pm\sqrt{(0)^2-4(1)(1)}}{2(1)}\\x=\frac{\pm\sqrt{-4}}{2}\\x=\frac{\pm2i}{2}\\x=\pm i

So, value of x is: x= i and x= -i

Keywords: Quadratic formula

Learn more about quadratic formula at:

  • brainly.com/question/7361044
  • brainly.com/question/10666510
  • brainly.com/question/1332667

#learnwithBrainly

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The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders
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Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

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In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that \mu = 84, \sigma = 15

Sample of 188

This means that n = 188, s = \frac{15}{\sqrt{188}}

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

Z = \frac{X - \mu}{\sigma}

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Z = \frac{X - \mu}{s}

Z = \frac{82.54 - 84}{\frac{15}{\sqrt{188}}}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

2*0.0918 = 0.1836

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

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