Answer:
Define a variable and write an expression for each phrase.
9. 2 more than twice a number
10. a number minus 11
11. 9 minus a number
12. a number divided by 82
13. the product of 5 and a number
14. the sum of 13 and twice a number
15. the quotient of a number and 6
16. the quotient of 11 and a number
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Seven add five is 12 . A clock has four quarters , the first quarter is fifteen minutes.
Therefore, 5 1/5 hours after 7:00 = 12:15
Answer:
y = -2x + 5
Step-by-step explanation:
