Answer:

Step-by-step explanation:
<u>Given equation</u>:

This is an equation for a horizontal hyperbola.
<u>To complete the square for a hyperbola</u>
Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

Factor out the coefficient of the x² term and the y² term.

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:


Factor the two perfect trinomials on the left side:

Divide both sides by the number of the right side so the right side equals 1:

Simplify:

Therefore, this is the standard equation for a horizontal hyperbola with:
- center = (1, 2)
- vertices = (-2, 2) and (4, 2)
- co-vertices = (1, 0) and (1, 4)


The value of x from the given diagram is 16.6
<h3>Secant-secant theorem</h3>
In order to determine the value of x from the given figure, we will use the secant-secant theorem shown by the equation.
(6 +12) * 6 = (5 + x) * 5
Expand
36+72 = 25 + 5x
108 = 25 + 5x
5x = 108 - 25
5x = 83
x = 83/5
x = 16.6
Hence the value of x from the given diagram is 16.6
Learn more on secant-secant theorem here: brainly.com/question/26826991
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Answer:
5
Step-by-step explanation:
Create an equation 9.99+0.35t≤12
solve for t
Answer:
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Step-by-step explanation: