The sum of measures of two alternate interior angles of two parallel lines with a transversal is 210°. What are the possible mea
sures of the angles formed by the parallel lines and the transversal?
1 answer:
<u>Solution-</u>
If the lines are parallel, then the alternate interior angles are congruent.
As the sum of measures of the two alternate interior angles = 210°
⇒ Measure of one alternate interior angles = 105°
Since a straight angle contains 180º, the two angles forming a linear pair also contain 180º when their measures are added (making them supplementary).
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1) The slope of the point (0,0) and (2,1) is 1/2.
2) The slope of the point (0,-1) and (2,-5) is -2.
3) The slope of the point (0,7) and (2,4) is -3/2.
4) The points (-1,3) and (-1,-3) has No slope.
5) The slope of the point (1,-3) and (-1,-3) is zero.
<u>Step-by-step explanation:</u>
There are five set of points given in the question.
You need to find out the slope of the line formed by the points.
The formula used to find the slope of a line is given by,
Slope =
1) The given points are (0,0) and (2,1)
(x1,y1) ⇒ (0,0)
(x2,y2) ⇒ (2,1)
Slope =
⇒ 1/2 is the slope.
2) The given points are (0,-1) and (2,-5)
(x1,y1) ⇒ (0,-1)
(x2,y2) ⇒ (2,-5)
Slope =
⇒
⇒ -2 is the slope.
3) The given points are (0,7) and (2,4)
(x1,y1) ⇒ (0,7)
(x2,y2) ⇒ (2,4)
Slope =
⇒ -3/2 is the slope.
4) The given points are (-1,3) and (-1,-3)
(x1,y1) ⇒ (-1,3)
(x2,y2) ⇒ (-1,-3)
Slope =
⇒ -6/0 (No slope)
If the denominator of a fraction is zero, the expression is not a legal fraction because it's overall value is undefined.
∴ There is no slope.
5) The given points are (1,-3) and (-1,-3)
(x1,y1) ⇒ (1,-3)
(x2,y2) ⇒ (-1,-3)
Slope =
⇒ 0/-2
∴ The slope is zero.