The sum of two numbers are 21the second number is six times the first numberwhat are the two numbers

Mathematics

2 answers:

Paha777 [63]2 years ago

6 0

Answer:

3+18

Step-by-step explanation:

3x6 is 18, so 18 is 6 times the first number. If you add 3 and 18, its equal to 21.

Ugo [173]2 years ago

4 0

Answer:

3+18=21

Step-by-step explanation:

first see the second number

let us assume as x & y

3+ (3×6)= 21

3+18=21Step-by-step explanation:

You might be interested in

Pls help I will mark brainlyesd

aev [14]

First, we have to solve for x by isolating it on one side.
6x + 10 = -8
(Subtract 10 from both sides)
6x = -18
(Divide both sides by 6)
x = -3

On option C, x is on -3, so that would be the correct answer

7 0

3 years ago

I am so stuck! :( Pls help me!!! I don't get the problem and I don't know how to solve it

Lelu [443]

Answer:

$\frac{n^{2}}{2a}$

Step-by-step explanation:

Just split it up first $\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}$
Then 9 divided by 18 can be simplified into the fraction 1/2
What can go into $a$ and $a^2$ ? a itself right, so if you divide a by a you get 1, if you divide $a^2$ by a you get a
Same as the a fraction, if you divide $n^3$ by n you get $n^2$
$\frac{9an^{3}}{18a^{2}n}=\frac{9}{18}\times \frac{a}{a^2} \times\frac{n^3}{n}=\frac{1}{2}\times \frac{1}{a} \times\frac{n^2}{1}=\frac{n^{2}}{2a}$