The simplest way is to count each "line"
For example, #2
We start at J, which is at -5
Count the lines all the way to L, at 3
Distance would be 8
The probability that it will be the winning combination is 1/(27C6) = 1/296010
When a line is bisected, it is divided into two congruent sides. Because triangle AYX is bisected, it is divided into two congruent sides, which are represented by Triangle YXZ and Triangle YAZ
So the answer is True