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elena55 [62]
3 years ago
12

20%5Cleft%28n%5Cright%29%7D%7Bn%5E2%7D" id="TexFormula1" title="\sum _{n=0}^{\infty \:}\frac{\left(-1\right)^n\arctan \left(n\right)}{n^2}" alt="\sum _{n=0}^{\infty \:}\frac{\left(-1\right)^n\arctan \left(n\right)}{n^2}" align="absmiddle" class="latex-formula">  Please Help. 
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

-1/00 should be the answer

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Suppose a man offered to work for 30 days at the following salary: one cent for the first day two cents for the second day four
Ivahew [28]
It would be to little because it would only be 30 cents
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Show me how to make 33 in four different ways
tamaranim1 [39]
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(sorry if these didn't help i'm a beginner and i'm in 7th grade)


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How much greater is the area of a a square with a side length of 8 inches than the area of a circle with radius of 4 inches?
expeople1 [14]
Area of a square= l²
                           = 8×8 = 64 in²

Area of  a circle= πr²
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7 0
3 years ago
Solve for x: −3|x − 3| = −6
lozanna [386]
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|x-3|=2
assume
x-3=2 and
x-3=-2

x-3=2
add 3
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7 0
3 years ago
Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)
lisov135 [29]
In short, (h o g)(a) is just h(    g(a)    ).

so what we can do is simply get g(a) first and then plug that in h(x).

\bf \begin{cases}
g(x)&=2x\\
h(x)&=x^2+4\\
(h\circ g)(a)&=h(~~g(a)~~)
\end{cases}
\\\\\\
g(a)=2(a)\implies g(a)=2a
\\\\\\
h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4
\\\\\\
h(~~2a~~)=(2^2a^2)+4\implies  h(~~2a~~)=4a^2+4
8 0
3 years ago
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