It would be to little because it would only be 30 cents
30+3
11*3
10*3+3
60-30+3
(sorry if these didn't help i'm a beginner and i'm in 7th grade)
Area of a square= l²
= 8×8 = 64 in²
Area of a circle= πr²
= π × 4²
= 50.3 in²
Difference = 64 - 50.3 = 13.7 in²
-3|x-3|=-6
divide both sides by -3
|x-3|=2
assume
x-3=2 and
x-3=-2
x-3=2
add 3
x=5
x-3=-2
add 3
x=1
x=5 or 1
In short, (h o g)(a) is just h( g(a) ).
so what we can do is simply get g(a) first and then plug that in h(x).