<img src="https://tex.z-dn.net/?f=%5Csum%20_%7Bn%3D0%7D%5E%7B%5Cinfty%20%5C%3A%7D%5Cfrac%7B%5Cleft%28-1%5Cright%29%5En%5Carctan%

3 years ago

20%5Cleft%28n%5Cright%29%7D%7Bn%5E2%7D" id="TexFormula1" title="\sum _{n=0}^{\infty \:}\frac{\left(-1\right)^n\arctan \left(n\right)}{n^2}" alt="\sum _{n=0}^{\infty \:}\frac{\left(-1\right)^n\arctan \left(n\right)}{n^2}" align="absmiddle" class="latex-formula"> Please Help.

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

8 0

-1/00 should be the answer

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<h3>How to determine the value of P(B)?</h3>

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