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muminat
3 years ago
13

How did lavoisier revolutionize the science in chemistry

Chemistry
1 answer:
Tanya [424]3 years ago
3 0
Lavoisier revolutionised chemistry science with his discovery of the role oxygen plays in combustion. He recognised and labelled the elements oxygen and hydrogen; he was also largely opposed to the phlogiston theory which dictates that a fire-like element called phlogiston is contained within combustible elements and is released during combustion. These were his most noted contributions to science.
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What is the madd in grams of 0.40 moles of sodium borohydride, NaBH4
Orlov [11]

Answer:

Mass = 15.1 g

Explanation:

Given data:

Number of moles of NaBH₄ = 0.40 mol

Mass in gram = ?

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of NaBH₄ = 37.83 g/mol

By putting values,

Mass = 0.40 mol × 37.83 g/mol

Mass = 15.1 g

3 0
3 years ago
How can a Hydrogen atom turn into a<br> Hydrogen ion (H+)?
Butoxors [25]

Answer:

By losing an electron

Explanation:

Electrons have a negative charge. So, losing one would give an element a more positive charge. You can usually find a hydrogen ion (H+) in substances like acids.

3 0
3 years ago
Formula Silver(II) Oxide ​
Svetach [21]

Answer:

AgO

Explanation:

5 0
3 years ago
N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?
just olya [345]

Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}

(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

7 0
3 years ago
Read 2 more answers
Compare a mixture and a compound. How are they alike?
LenKa [72]

Answer:

gnzl8303

gnzl8303vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Explanation:

8 0
4 years ago
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