Answer:
w₁ = 0 J
w₂ = -297 J
Explanation:
Step 1: Given data
Initial volume: 266 mL (0.266 L)
Final volume: 983 mL (0.983 L)
Step 2: Calculate the work done (in joules) by the gas if it expands against a vacuum
We will use the following expression.
w₁ = -P₁ × ΔV
Since the gas expands against a vacuum, P₁ = 0. Thus, w₁ = 0 J
Step 3: Calculate the work done (in joules) by the gas if it expands against a constant pressure of 4.09 atm
We will use the following expression.
w₂ = -P₂ × ΔV
w₂ = -4.09 atm × (0.983 L-0.266 L) = -2.93 atm.L
Then, we convert w₂ to Joule using the conversion factor 1 atm.L = 101.325 J.
-2.93 atm.L × 101.325 J/1 atm.L = -297 J
Answer:
See explanation
Explanation:
Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.
In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.
Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.
The rate of a chemical reaction can be raised by increasing the surface area of a solid reactant. This is done by cutting the substance into small pieces, or by grinding it into a powder.
Answer:
Explanation:
CH₃COOH + NaOH = CH₃COONa + H₂O .
42.5 mL of .115 M of NaOH will contain .0425 x .115 moles of NaOH
= 48.875 x 10⁻⁴ moles NaOH
It will react with same number of moles of acetic acid
So number of moles of acetic acid in 3.45 mL = 48.875 x 10⁻⁴
number of moles of acetic acid in 1000 mL = 48.875 x 10⁻⁴ x 10³ / 3.45 moles
= 1.4167 moles
= 1.4167 x 60 gram
= 85 grams .
So 85 grams of acetic acid will be contained in one litre of acetic acid.
Answer:
XZ2
Explanation:
There are different ways in which compounds can be represented. Broadly, we have three different types of formula;
- Structural formular: This shows how th atoms in te compound are connected to each other.
- Molecular formular: This shows the actual number of atoms of element present in the compound
- Empirical Formular: This is the simplest formular of a compound. It basically shows the number of atoms in simple ration to each other.
This question requires us to input the empirical formular;
X2Z4
The ratio of the elements is; 2 : 4 which can be simplified into 1 : 2
This means the empirical formular is XZ2
