Answer:
2Cu2^+ + 2I^- ----> 2Cu^+ + I2
Explanation:
The reaction performed in the experiment is;
2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2
The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.
The oxidation - reduction equation is as follows;
2Cu2^+ + 2e ----> 2Cu^+ reduction half equation
2I^- ----> I2 + 2e. Oxidation half equation
Balanced redox reaction equation;
2Cu2^+ + 2I^- ----> 2Cu^+ + I2
Answer:
ΔG° = -533.64 kJ
Explanation:
Let's consider the following reaction.
Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)
The standard Gibbs free energy (ΔG°) can be calculated using the following expression:
ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)
where,
ni are the moles of reactants and products
ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products
ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)
ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)
ΔG° = -533.64 kJ
Answer:
6.00 moles of sodium permanganate
Explanation:
Let us attempt to count the number of atoms present in sodium perchlorate. The formula of the compound is NaClO4
Sodium atoms - 1
Chlorine atoms - 1
Oxygen atoms -4
Total number of atoms = 6
Among the options, only KMnO4 also has six atoms. One atom of potassium, one atom of manganese and four atoms of oxygen.
Answer:
0.45 g
Explanation:
Step 1: Given data
- Molar mass of methionine (M): 149.21 g/mol
- Volume of the solution (V): 20 mL
- Concentration of the solution (C): 150 mM
Step 2: Calculate the moles of methionine (n)
We will use the following expression.
n = C × V
n = 150 × 10⁻³ mol/L × 20 × 10⁻³ L
n = 3.0 × 10⁻³ mol
Step 3: Calculate the mass of methionine (m)
We will use the following expression.
m = n × M
m = 3.0 × 10⁻³ mol × 149.21 g/mol
m = 0.45 g
The purpose is that it shows you all the elements we know and it arranges them in groups that are also the same kind like Chemistry.
