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horrorfan [7]
3 years ago
8

Show by direct proof the sum of two odd integers is an even integer.

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
I believe this is right, please correct me if not!

Good luck!

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40 students at a particular school are randomly selected for a survey. 18 have blue eyes. If there are 400 students at this scho
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A reasonable estimate would be 180 students with blue eyes
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3 years ago
Read 2 more answers
Write the order of operations down using your own words​
dybincka [34]

The order of operations is:

Parentheses, Exponent, Division, Multiplication, Addition, Subtraction.

Or PEMDAS.

hope it helps!

6 0
3 years ago
Henry buys a large boat for the summer, however he cannot pay the full amount of $32,000 at
Anna007 [38]

Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

Step-by-step explanation:

Loan payment per month=Amount to pay÷discount factor

Mathematically  P=A÷D

where D is the discount factor calculated using the formula;

\frac{(1+i)^n-1}{i(1+i)^n}

where i=periodic interest rate=annual rate divided by number of payment periods

A is the amount to pay after downpayment

P is the loan monthly payment amount

n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

Periodic payments, n=4×12=48

Finding the discount factor D;

D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05

To get the amount to pay monthly divide the loan to pay with the discount factor

=\frac{18000}{43.05} =418.14

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

8 0
3 years ago
Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?
Sveta_85 [38]
^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\  \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right


Answer: system nr 4.
7 0
3 years ago
Solve the exponent equation for x 7(4x-6)= 1/49
tatiyna
X=1. Chose C. Hoped that will help
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