Answer:
The lower bound of a 99% C.I for the proportion of defectives = 0.422
Step-by-step explanation:
From the given information:
The point estimate = sample proportion 
= 0.55
At Confidence interval of 99%, the level of significance = 1 - 0.99
= 0.01
Then the margin of error 
E = 0.128156
E ≅ 0.128
At 99% C.I for the population proportion p is: 
= 0.55 - 0.128
= 0.422
Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422
Cody because 18 out of 20 is %90 and 24 out of 30 is %80
Answer:
2.1 hrs
Step-by-step explanation:
In 1 hr, Phillip would have proofed 1/7 of the chapter. In 1 hr, Kim would have proofed 1/3 of the chapter. So, together in 1 hr, they would have proofed 10/21 of the chapter. So, it would take 21/10 or 2.1 hrs to proof the whole chapter together.
Answer:
definition the set of positive real number which greater than 0 are the nonnegative number. for ex=(1,2,3...10)
You have to plug them in to see each solution, so the answers that apply would be 65 and 66 all the other answers are less than or equal to 8
