Answer:
$848
Step-by-step explanation:
Calculation for the cost of this familiy's clothing in 1991
First step is to calculate the amount that is increase per year
Increase per year= ($1000-$620)/(1995-1985)
Increase per year= 380/10
Increase per year= $38
Now let y be :38*x + $620 and let x be 6 years (1991-1985)
Second step is to calculate the cost of the clothing in 1991
y = 38*6 + 620
y=228+620
y = $848
Therefore the cost of this familiy's clothing in 1991 will be $848
Answer:
4x+12/x^2+9
Step-by-step explanation:
Perimeter
x+3+x+3+x+3+x+3
Area
(x+3)(x+3)
Answer:
Step-by-step explanation:
Square root can be written as a power.
Multiply the exponents.
The calculation uses the accumulated daily balance method (ADB).
We assume the statement is based on calendar month (rare!).
George owes $500 from beginning to end of June, so 30 days out of 30.
Interest accrued is 500*0.013*30/30=$6.50.
He also owes $2000 from June 12 to June 30, so 19 days inclusively.
Interest accrued is $2000*.013*(19/30)=16.47
Total interest at the end of the month=$6.50+$16.47=$22.97
Hi Dezariaspencer
All we have to do is simply add 2x to both sides and we have our answer.
Answer: y = 11 + 2x.
Thank you for asking your question, have a good day.
