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guajiro [1.7K]
3 years ago
10

Point P was rotated about the origin (0,0) by 105

Mathematics
1 answer:
Alex3 years ago
4 0

Answer:

A

Step-by-step explanation: I got it right

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a farm, in the shape of an isosceles trapezoid, is putting up fences on its diagonals. If 1 fence has sixteen 9 - foot segments,
iragen [17]

Answer:

18

Step-by-step explanation:

16 × 9 = 8 × x

x = 18

3 0
3 years ago
Please please please help me with math
aivan3 [116]

Answer:

30 dollars

Step-by-step explanation:

The y-intercept is 15 and the slope is 30

How?

slope = change in y/change in x

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3 years ago
A number is greater than 8. The same number is less than 10. The inequalities x > 8 and x < 10 represent the situation.
Semenov [28]

Answer:

There are infinite solutions because there is always another number between any two numbers.

Step-by-step explanation:

Pick any number (including decimal) add an extra decimal after the smallest one and then you have a number between them. E.g.

1.234 and 2.987

1.2341, 1.2342, 1.2343, ... are all between them

7 0
3 years ago
Read 2 more answers
HELP Plssss..... The m
hammer [34]

Answer:

Step-by-step explanation:

Hey there!!!

According to the question,

Angle P is three less than twice less of an angle Q.

Then, let angle Q be x then angle P is 2x-3.

Now, it has also given that they are supplementary angle.

We know that the sum of supplementary angle is 180°.

Therefore, x+ 2x - 3°=180°.

Or, 3x = 180°-3°

Or, x = 177°/3

Therefore the measure of angle Q is 59° and P is 2×59°-3°= 121°.

Hope it helps....

6 0
3 years ago
A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At
Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

The particle starts at rest, so v(0)=0, and we have

v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t

Then the position function is

x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du

with x(0)=6, so

x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t

b. The particle is at rest whenever v(t)=0; this happens for

6\sin t=0\implies \sin t=0\implies t=n\pi

where n is any integer.

3 0
3 years ago
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