What is the circumference of a circle with a diameter of 8 feet? Use 3.14 for TT. d = 8 ft
2 answers:
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The function is supposed to be;
h(x) = -343^(x)
Answer:
The domain will be a set of real numbers while the range will be y ≤ 0 and on the interval (-∞, 1)
As x is increasing, h is decreasing and as x is decreasing, h is increasing
Step-by-step explanation:
We are given the function as;
h(x) = -343^(x)
The formula is;
y = a^(x) since it's symmetrical to the x-axis
However in this case;
y = -a^(x)
Now, the domain is y and the range is a set of values of x.
I've attached a graph of this function drawn on desmos.
From the graph we can see that The domain will be a set of real numbers while the range will be on the interval (-∞, 1)
For a value of x = 0,we have;
h(0) = -343^(0)
h(0) = -343
When we increase the value of x to 3,we have;
h(3) = -343^(3)
h(3) = -40353607
When we decrease the value of x to -3, we have;
h(-3) = -343^(-3)
h(-3) = 0.00000002478
Thus, we can conclude that;
As x is increasing, h is decreasing and as x is decreasing, h is increasing
