Answer:
The graph represent a scatter plot between variable A on the horizpntal line and the variable B on the vertical line.
A line of best fit is a straight line drawn through the maximum number of points on a scatter plot balancing about an equal number of points above and below the line.
As shown by graphinf a line through the maximum number of points, balancing about an equal number of points above and below the line, we can deduce that:
<u>The line of best fit drops from left to right, so the variables have a negative correlation. </u>
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:

Hence the derivative is:

For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
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✿————✦————✿————✦————✿
This is the answer:
✿————✦————✿————✦————✿
Step:
* To raise a power to another power, multiply the exponents. Multiply 1/2 and −2 to get −1.
* To raise a power to another power, multiply the exponents. Multiply −1/4 and −2 to get 1/2.
Answer:
0.64π rad
Step-by-step explanation:
The formula for calculating the length of an arc is expressed as;
length of an arc = theta/360 * 2πr
r is the radius = 13 feet
arc length = 26feet
Substitute
26 = theta/360 * 2(3.14)(13)
26 = 81.64 theta/360
81.64 theta = 26 * 360
81.64 theta = 9360
theta = 9360/81.64
theta = 114.64
Hence the radian measure is 114.64/180 π = 0.64π rad
Answer:
here you goes hope it helps you
Step-by-step explanation:
1
Common factor
−
3
2
+
7
+
2
0
-3y^{2}+7y+20
−3y2+7y+20
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}-7y-20)
−1(3y2−7y−20)
2
Use the sum-product pattern
−
1
(
3
2
−
7
−
2
0
)
-1(3y^{2}{\color{#c92786}{-7y}}-20)
−1(3y2−7y−20)
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)
−1(3y2+5y−12y−20)
3
Common factor from the two pairs
−
1
(
3
2
+
5
−
1
2
−
2
0
)
-1(3y^{2}+5y-12y-20)
−1(3y2+5y−12y−20)
−
1
(
(
3
+
5
)
−
4
(
3
+
5
)
)
-1(y(3y+5)-4(3y+5))
−1(y(3y+5)−4(3y+5))
4
Rewrite in factored form
Solution
−
1
(
−
4
)
(
3
+
5
)