Given that I no not see any explanation in the previos answer, I think you can benefit of this.
Exothermic refers only to the fact that the reaction releases energy in the form of heat when occurs. So, the enthalpy is higher at start and lower and the end.
Seen in this way, you can deduct that the change in enthalpy is negative, which is what the third option says.
Whats the answer
i am working on the same test right now
Answer:
Future amount (A) = $1,258.77 (Approx)
Step-by-step explanation:
Given:
Amount deposit (p) = $693
Rate of interest monthly (r) = 4.9% / 12 = 0.003833
Number of month (n) = 13 × 12 = 156
Find:
Future amount (A)
Computation:
![A = p [1+r]^n \\\\ A = 693 [1+0.003833]^{156}\\\\ A= 693[1.8163]\\\\ A = 1258.77](https://tex.z-dn.net/?f=A%20%3D%20p%20%5B1%2Br%5D%5En%20%5C%5C%5C%5C%20A%20%3D%20693%20%5B1%2B0.003833%5D%5E%7B156%7D%5C%5C%5C%5C%20A%3D%20693%5B1.8163%5D%5C%5C%5C%5C%20A%20%3D%201258.77)
Future amount (A) = $1,258.77 (Approx)
Answer:

Step-by-step explanation:
<u>step(i)</u>
Given function y = 3 x³ - 2 x ... (i)
Differentiating equation (i) with respective to 'x'

Given x = -2


<u><em>Step(ii):-</em></u>
<u><em>we know that </em></u>

Given 

substitute values
⇒ 
cross multiplication , we get

<u><em>Final answer</em></u>:-

The value of x is -2 and the value of y is -1.
Step-by-step explanation:
Step 1; The given equations are taken as
-3y -9x =21 or -9x -3y = 21, take this as equation 1
-18x +4y =32, take this as equation 2
Step 2; We multiply equation 1 with 2 and equation 2 with 1 so we can cancel out the variable x in both equations. By doing this we get
-18x -6y =42, take this as equation 3
-18x +4y =32, this is the same as equation 2
If we subtract 3 with 2, we cancel out the x variable and can calculate the value of y.
10y = -10 , y = -10/10 = -1
Step 3; Substituting this value of y in any of the previous equations we will get x's value. Here this value of y is substituted in equation 2.
-18x +4(-1) =32, -18x -4 = 32 , -18x = 36, x=-2.
So we have x = -2 and y = -1.