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Radda [10]
3 years ago
7

Find the value of x in the circle.

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

34

Step-by-step explanation:

You might be interested in
Solve 2x2 + 20x = −38.
Makovka662 [10]

Answer:

Correct Answer is C(−5 ±square root 6)

Step-by-step explanation:

2x^2+20x+38=0

2(x^2+10x+19)=0

x^2+10x+19=0

This is a quadratic equation here we have used following formula to find the roots of this equation

x=-b−±square root (b^2-4*a*c))/2*a......(1)

Here,

a=1

b=10

c=19

put values of a, b and c in equation (1)

x=(-10 ±square root(10^2-4*1*19))/2*1

x=(-10 ±square root(100-76))/2

x=(-10 ±square root(24))/2

x=(-10 ±square root(2*2*6))/2

x=(-10 ±2square root(6))/2

x=2(-5 ±square root(6))/2

x=-5 ±square root(6)


Hope this answer will help you

6 0
3 years ago
PLEASE HELP MEEEEEEEEEE
Nitella [24]

Answer: we are on venus

Step-by-step explanation:

6 0
3 years ago
Explain the purpose of statements
joja [24]
There is no picture.
5 0
3 years ago
How do i solve this?
Leni [432]

Answer: this is hard I hate math sorry

Step-by-step explanation:

:(

3 0
3 years ago
SOMEONE PLEASE HELP!!
german

-12=\dfrac{-12}{1}=\dfrac{12}{-1}=\dfrac{-24}{2}=\dfrac{24}{-2}=\dfrac{-36}{3}=\dfrac{36}{-3}=\dfrac{-48}{4}=\dfrac{48}{-4}=\dots

7 0
3 years ago
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