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densk [106]
4 years ago
15

Is (10,-10) a common solution for x-5>3 and -y>7?

Mathematics
2 answers:
const2013 [10]4 years ago
8 0
Yes. Sjakakakakakaks
fenix001 [56]4 years ago
6 0
\bf (\stackrel{x}{10}~~,~~\stackrel{y}{-10})
\\\\\\
\begin{cases}
x-5\ \textgreater \ 3\\
-y\ \textgreater \ 7
\end{cases}

is it?  let's check.

x-5>3     x = 10

(10) - 5 > 3

5 > 3      <----- hmmm is that really true?  5 is indeed greater than 3.

let's check the other condition, "y" being -10.

-y > 7      y = -10

-(-10) > 7

+10 > 7   <---- is 10 greater than 7 really?  well, yes it is.

since the coordinates of 10, -10, provide a "true" value for each inequality, then 10,-10 is a solution.
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