Determine if the given ordered pairs are solution of x+ 4y = 7.

Mathematics

1 answer:

const2013 [10]3 years ago

6 0

Answer:

(3, 1 ) is a solution

Step-by-step explanation:

To determine if the given points are solutions, substitute the x and y values into the left side of the equation and if equal to the right side then they are solutions.

(3, 1 )

3 + 4(1) = 3 + 4 = 7 = right side , then a solution

(2, 1 )

2 + 4(1) = 2 + 4 = 6 ≠ 7 ← not a solution

You might be interested in

"(b) use part (a) to find a power series for f(x) = 1 (4 + x)3 ."

Firdavs [7]

Assuming

$f(x)=\dfrac1{(4+x)^3}$

Recall that for $|x|$ ,

$\displaystyle\sum_{n\ge0}x^n=\frac1{1-x}$

Denote the above by $s(x)$ . Then

$s'(x)=\displaystyle\sum_{n\ge1}nx^{n-1}=\frac1{(1-x)^2}$
$s''(x)=\displaystyle\sum_{n\ge2}n(n-1)x^{n-2}=\frac2{(1-x)^3}$

Now,

$\dfrac1{(4+x)^3}=\dfrac1{4^3}\dfrac1{\left(1-\left(-\frac x4\right)\right)^3}=\dfrac1{2^7}\dfrac2{\left(1-\left(-\frac x4\right)\right)^3}$

which means we have

$f(x)=\dfrac1{2^7}s''(x)=\dfrac1{128}\displaystyle\sum_{n\ge2}n(n-1)\left(-\frac x4\right)^{n-2}$

which is valid for $\left|-\dfrac x4\right|$ , or $|x|$ .

4 0

3 years ago

Explain how to regroup 43 ones as tens and ones

zepelin [54]

The number 43 has 4 tens and 3 ones.

Now we have 43 ones given, in order to regroup them, we need to group 4 rows of 10 each and 3 rows of 1 each.

By this, we will be having:
4 rows of 10 each = 4*10 = 40
3 rows of 1 each = 3*1 = 3
which is the needed 43.

6 0

4 years ago

If the area of a circle is 64 square meters then what is the radius

s2008m [1.1K]

Answer:

Radius = 4.51

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Can anyone in the community help me solve these problema??

larisa86 [58]