1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Thepotemich [5.8K]
2 years ago
7

Determine if the given ordered pairs are solution of x+ 4y = 7.

Mathematics
1 answer:
const2013 [10]2 years ago
6 0

Answer:

(3, 1 ) is a solution

Step-by-step explanation:

To determine if the given points are solutions, substitute the x and y values into the left side of the equation and if equal to the right side then they are solutions.

(3, 1 )

3 + 4(1) = 3 + 4 = 7 = right side , then a solution

(2, 1 )

2 + 4(1) = 2 + 4 = 6 ≠ 7 ← not a solution

You might be interested in
I would do 100 points but i cant i only have 33 please give me the right answer or i will report
seraphim [82]

Answer:

  1. height
  2. width
  3. id-k
  4. width
  5. base
  6. square

Step-by-step explanation:

4 0
3 years ago
The probability for success of an event is P(A), and the probability of success of a second event is P(B). What is the probabili
Ilya [14]
D. P(A x B)

To work out the success of both events you have to multiply them together. I'd seriously reccomend learning this rule as it's very important later on in mathematics as it's basically the foundation of all probability statistics.
4 0
3 years ago
Read 2 more answers
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
Please answer this correctly
My name is Ann [436]

Description:

As we that that 3 of the students voted for counting .

4 Students voted for sorting

6 Students voted for shapes

7 Students voted for addition

Answer:

Counting - 3%

Sorting - 4%

Shapes-  6%

Addition-  7%

Please mark brainliest

<em><u>Hope this helps.</u></em>

8 0
3 years ago
Read 2 more answers
Please help i am being timed i beg you please help
Viefleur [7K]
There is no photo attached
6 0
2 years ago
Read 2 more answers
Other questions:
  • Trying to help my daughter with her 5th grade Math - Here is my question.
    15·2 answers
  • Is 26 a perfect square? Why or why not?
    5·2 answers
  • What is the equation of the quadratic graph with a focus of (−4, −five fourths) and a directrix of y = twenty seven fourths?
    11·2 answers
  • There are 13 boys and 15 girls in Ms. Green’s 3rd period math class. Five girls and four boys have already been called on today.
    11·1 answer
  • Solve -4.8=d-3.9<br><br>Enter only the value of the variable
    5·2 answers
  • 6<br> 20<br> 4<br> What is the area
    11·1 answer
  • Ground of the following nearest tens and Place a 7639. b_4325671​
    10·1 answer
  • 7.<br> State the slope of the line.<br><br> A. –2<br><br> B. 0<br><br> C. undefined<br><br> D. 1
    12·2 answers
  • Edward had a lump of play doh that was 2 1/2 inches long. If he stretched it out to 3 times its current length how long would it
    9·2 answers
  • Determine any data values that are missing from the table, assuming that the data represent a linear function.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!