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Vitek1552 [10]
3 years ago
8

Whats the point on the graph​

Mathematics
2 answers:
kirill115 [55]3 years ago
7 0
I believe the answer is (0,1)
Lerok [7]3 years ago
3 0

Answer:

0, 2

Step-by-step explanation:

im not sure tho

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Ath
jarptica [38.1K]

Answer:

1000

Step-by-step explanation:

Primo car rental agency charges $44 per day plus $0.10 per mile.

44+0.10m= 44.1

ultimo car rental: 26+0.55m=26.55

26 + 0.55m = 4 * (44 + 0.10m )

26 + 0.55m = 176 + 0.40m

26 + 0.55m - 0.40m = 176 + 0.40m - 0.40m

26 + 0.15m = 176

0.15m = 150

150/0.15m

m= 1000

5 0
4 years ago
Help if correct will give brainless
Jobisdone [24]
This is Very good correct
7 0
2 years ago
Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
4 years ago
URGENT! A ball gets hit upwards from a height of 5ft and an initial velocity of 200f/s. When does the ball hit the ground to the
Vinil7 [7]

Answer:

The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.

Step-by-step explanation:

5 0
3 years ago
Use the fact that the mean of a geometric distribution is μ= 1 p and the variance is σ2= q p2. A daily number lottery chooses th
butalik [34]

Answer:

a). The mean = 1000

     The variance = 999,000

     The standard deviation = 999.4999

b). 1000 times , loss

Step-by-step explanation:

The mean of geometric distribution is given as , $\mu = \frac{1}{p}$

And the variance is given by, $\sigma ^2=\frac{q}{p^2}$

Given : $p=\frac{1}{1000}$

             = 0.001

The formulae of mean and variance are :

$\mu = \frac{1}{p}$

$\sigma ^2=\frac{q}{p^2}$

$\sigma ^2=\frac{1-p}{p^2}$

a). Mean =   $\mu = \frac{1}{p}$

              = $\mu = \frac{1}{0.001}$

              = 1000

  Variance =   $\sigma ^2=\frac{1-p}{p^2}$

                  = $\sigma ^2=\frac{1-0.001}{0.001^2}$

                           = 999,000

   The standard deviation is determined by the root of the variance.

    $\sigma = \sqrt{\sigma^2}$

        = $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000  times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

  = $ 0.50

Since the answer is negative, we are expected to make a loss.

4 0
3 years ago
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