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Kaylis [27]
3 years ago
8

Suppose a playlist on an MP3 music player consists of 100 songs, of which six are by a particular artist. Suppose that songs are

played by selecting a song at random (with replacement) from the playlist. The random variable x represents the number of songs played until a song by this artist is played.
Explain why the probability distribution of x is not binomial.
Mathematics
1 answer:
madam [21]3 years ago
8 0
Because binomials is part of math and so is x
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Zoe has 8 cups of whole-wheat flour. If each loaf of her favorite bread requires Three-fourths of a cup of whole-wheat flour, ho
Alexxx [7]

Answer:

she can make 10 loaves

Step-by-step explanation:

If you need explanation, comment and I will go step by step.

5 0
3 years ago
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Which theorem or postulate proves that △ABC and △DEF are similar?
GaryK [48]
For similarity measures of corresponding angles should be equal so we would use AA similarity postulate
5 0
3 years ago
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Decide if the expression is positive or negative. Explain in words how you know, please.
AysviL [449]

Step-by-step explanation:

The first expression is :

-11\times \dfrac{2}{3}

Numerator = -11×2 = -22

Denominator = 3

So, answer will be :

-11\times \dfrac{2}{3}=\dfrac{-22}{3} (negative)

The second expression is:

-11\times \dfrac{-2}{3}

Numerator = -11×-2 = 22

Denominator = 3

So, the answer will be :

-11\times \dfrac{-2}{3}=\dfrac{22}{3} (positive)

Hence, this is the required solution.

7 0
2 years ago
Did I do this right?
exis [7]
No. For instance, let’s look at 1)
It’s asking you to find what x is when x/10 = 6

So, consider the equation x/10=6
Multiply both sides by 10, and your answer is 60.
Now do this for each one.
7 0
3 years ago
A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre
Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is <u>tested if the consumption is not different</u>, that is, if the subtraction of the means is 0, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is <u>tested if the consumption is different</u>, that is, if the subtraction of the means is not 0, hence:

H_1: \mu_1 - \mu_2 \neq 0

Two groups of 22 patients, hence, the standard errors are:

s_1 = \frac{45.1}{\sqrt{22}} = 9.6154

s_2 = \frac{26.4}{\sqrt{22}} = 5.6285

The distribution of the differences is has:

\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25

s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{25 - 0}{11.14}

t = 2.2438

The p-value of the test is found using a <u>two-tailed test</u>, as we are testing if the mean is different of a value, with <u>t = 2.2438</u> and 22 + 22 - 2 = <u>42 df.</u>

  • Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0
3 years ago
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