Answer:
Step-by-step explanation:
Slope of line through the three points is -3.
Slope of any perpendicular through the line is ⅓.
(0,1) is one of the points on the line, so the y-intercept is 1.
Slope-intercept equation for line of slope ⅓ and y-intercept 1:
y = ⅓x+1
You cant solve these if they are not equating up to something hence incomplete question.
That is an annuity and use the attached formula.
Total = 300 * [(1.055)^11 -1] / .055 -300
Total = 300 *
<span>
<span>
<span>
1.8020924036
</span>
</span>
</span>
-1 /.055 -300
Total = 300 *
<span>.8020924036 / .055 - 300
</span>Total = 300 *
<span>
<span>
<span>
14.5834982473
</span>
</span>
</span>
-300
Total =
<span>
<span>
<span>
4375.0494741818
</span>
</span>
</span>
-300
Total =
<span>4075.05
</span>
Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
_____
<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.