3 years ago

A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

Mathematics

1 answer:

Anton [14]3 years ago

6 0

Answer: Y= -3/4x+13

Step-by-step explanation:

A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

This is what i get

Slope of a line Y= mx+b

Y= 7

X= 8

M= -3/4

7= -3/4(8)+b

7= -6+b

7+6=b

13=b

Y= -3/4x+13

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The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

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$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

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Express 1 as cos°(Ф)

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brainly.com/question/8120556

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