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2 years ago

A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

Mathematics

1 answer:

Anton [14]2 years ago

6 0

Answer: Y= -3/4x+13

Step-by-step explanation:

A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.

This is what i get

Slope of a line Y= mx+b

Y= 7

X= 8

M= -3/4

7= -3/4(8)+b

7= -6+b

7+6=b

13=b

Y= -3/4x+13

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following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

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$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

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$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

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Step-by-step explanation:

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