Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true
Answer:
AAS
Step-by-step explanation:
Answer:
X= -7 ± √17 / 16
x= - 0.7798...
Step-by-step explanation:
Answer:
1 gamma = 15/8 alphas
Step-by-step explanation:
so we start by finding out what 1 gamma and 1 beta equals.
we know 4 gammas = 5 betas so if we divide by four on both sides we get:
1 gamma = 5/4 betas. we can apply that same procedure to 2 betas = 3 alphas and get 1 beta = 3/2 alphas
we know that 1 gamma = 5/4 betas and 1 beta = 3/2 alphas so how many alphas = 5/4 betas? using a proportion of ((3/2)/1) = ((x)/(5/4)) we can find that 5/4 betas = 15/8 alphas
therefore we know 1 gamma = 15/8 alphas or 1 and 7/8 alphas
