1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex73 [517]
4 years ago
8

What are the factor that affect the efficiency of a pulley​

Physics
1 answer:
alukav5142 [94]4 years ago
8 0

Answer:

Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.

Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)

Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.

Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.

Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.

Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.

Explanation:

You might be interested in
You have gathered green turtle hatchlings from a beach where the magnetic field strength is 50 μT and the dip angle is 56∘. You
svet-max [94.6K]

Answer:

Explanation:

Angle of dip = 56° , magnetic field strength = 50μT

Vertical component = 50 x sin 56 = 41.45 μT

Horizontal component = 50 cos 56 = 27.96μT

New field is added in vertical downwards direction to increase the vertical component so as to increase the angle of dip . Let this field be B

total vertical field = B +  41.45

Horizontal component = 27.96

dip angle be θ

tanθ = vertical component / horizontal component

tan62 = B +  41.45 / 27.96

1.88 = B +  41.45 / 27.96

52.58 = B +  41.45

B = 11.13 μT

Since magnetic field has to be added , current should be clockwise when looked from above.

8 0
3 years ago
A man whose mass is 90 kg is 6.38x106m away from the center of the earth. If the Earth’s mass is6x1024kgand the constant Gis 6.6
inysia [295]

Answer: force of gravity is 885N

Explanation:

8 0
3 years ago
Read 2 more answers
Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8
guapka [62]
Hi, thank you for posting your question here at Brainly.

This problem could be solved using this equation:

Diffraction limit = 1.22*wavelength/diameter

diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m

Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
6 0
3 years ago
Two protons are 9.261 fm apart. (1 fm= 1 femtometer = 1 x 10^-15 m.) What is the ratio of the electric force to the gravitationa
Strike441 [17]

Answer:

1.24\times 10^{36}

Explanation:

q = magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C

m = mass of each proton = 1.67 x 10⁻²⁷ kg

r = distance between the two protons = 1 x 10⁻¹⁵ m

Electric force between the two protons is given as

F_{e} = \frac{kq^{2}}{r^{2}}

F_{e} = \frac{(9\times 10^{9})(1.6\times 10^{-19})^{2}}{(1\times 10^{-15})^{2}}

F_{e} = 230.4 N

Gravitational force between the two protons is given as

F_{g} = \frac{Gm^{2}}{r^{2}}

F_{g} = \frac{(6.67\times 10^{-11})(1.67\times 10^{-27})^{2}}{(1\times 10^{-15})^{2}}

F_{g} = 1.86\times 10^{-34} N

Ratio is given as

Ratio =\frac{F_{e}}{F_{g}}

Ratio =\frac{230.4}{1.86\times 10^{-34}}

Ratio = 1.24\times 10^{36}

3 0
3 years ago
Read 2 more answers
Suppose an automobile engine can produce 180 N*m of torque, and assume this car is suspended so that the wheels can turn freely.
morpeh [17]

Answer:

Explanation:

Moment of inertia of each wheel = 1/2 m R²

m is mass and R is radius of wheel

= .5 x 15.5 x .175²

= .2373 kg m²

moment of inertia of tyre

1/2 m ( r₁² + r₂² )

= 1/2 x 1.9 x ( .315² + .19²)

= 1/2 x 1.9 x ( .099+ .036)

= .12825 kg m²

moment of inertia of tread

= 1/2 m r²

= .5 x 12 x .335²

= .67335 kg m²

moment of inertia of axle

= 1/2 m r ²

= .5 x 14.5 x .0195²

= .00275

moment of inertia of drive shaft

= 1/2 x 32.5 x .029²

= .0137 kg m ²

Total moment of inertia of one tyre

=  1.05535 kg m²

total moment of inertia of two rear wheels

= 2.1107 kg m²

95 % of torque

= .95 x 180

= 171 Nm

angular acceleration

= torque / moment of inertia

= 171 / 2.1107

= 81.01 radian /s²

3 0
3 years ago
Other questions:
  • a bicycle pump contains 20cm3 of air at a pressure of 100kpa the air is then pumped in a single stroke through a valve into a ty
    8·1 answer
  • How does the movement of particles of matter change when temperature decreases
    12·1 answer
  • An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will be
    5·1 answer
  • Tectonic plates often shift position by the force of liquid rock emerging from below the Earth’s surface and then cooling to for
    8·2 answers
  • At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took
    7·2 answers
  • A copper cable needs to carry a current of 160 A with a power loss of only 2.0 W/m. What is the required radius of the copper ca
    13·1 answer
  • Humans and fish brains are similar because they both have a?
    10·1 answer
  • What determines the precision of a measurement?
    9·1 answer
  • Plz help me with this question ​
    12·1 answer
  • Plz Help
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!