The main formula to be used here is
Force = (mass) x (acceleration).
We'll get to work in just a second. But first, I must confess to you that I see
two things happening here, and I only know how to handle one of them. So
my answer will be incomplete, but I believe it will be more reliable than the
first answer that was previously offered here.
On the <u>right</u> side ... where the 2 kg and the 3 kg are hanging over the same
pulley, those weights are not balanced, so the 3 kg will pull the 2kg down, with
some acceleration. I don't know what to do with that, because . . .
At the <em>same time</em>, both of those will be pulled <u>up</u> by the 10 kg on the other side
of the upper pulley.
I think I can handle the 10 kg, and work out the acceleration that IT has.
Let's look at only the forces on the 10 kg:
-- The force of gravity is pulling it down, with the whatever the weight of 10 kg is.
-- At the same time, the rope is pulling it UP, with whatever the weight of 5 kg is ...
that's the weight of the two smaller blocks on the other end of the rope.
So, the net force on the 10 kg is the weight of (10 - 5) = 5 kg, downward.
The weight of 5 kg is (mass) x (gravity) = (5 x 9.8) = 49 newtons.
The acceleration of 10 kg, with 49 newtons of force on it, is
Acceleration = (force) / (mass) = 49/10 = <em>4.9 meters per second²</em>
10 electrons are in a water molecule. :)
Answer and explanation:
A.
Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)
B.
In muon rest frame it travels Zero meters
C.
Distance, d = Velocity, v * Time, s


D.
Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame
that is same as in part C which is 594m
E.
Using lorentz contraction
In the rest frame of someone standing on the mountain
the distance is given by




d' = 258.92m
F.
in the rest frame of someone standing on the mountain,
muon moves straight down
atomic mass of carbon is C = 12 g/mol
atomic mass of hydrogen is H = 1 g/mol
now number of carbon atoms

Similarly the number of hydrogen atoms are

so Carbon atom and hydrogen atom must be in ratio of 10:30
so the ratio is 1:3
now the empirical formula is always in simplest form

The Hubble Telescope or Hubble Space Telescope (HST) is designed to take images found within the solar system. It is a low-orbit kind of telescope that helped a lot of scientists in proving some theories in astrophysics and the dimensions of the Universe. It was launched in 1990s and since then has been in space taking up good quality images that would help scientists learn more from space explorations.