Before taking a pressure reading, it is necessary for the technician to first allow the temperature of the cylinder to stabilize to room temperature because a comparison with a temperature-pressure chart is only valid and true when both temperature and pressure of the refrigerant are stable.
We could use the change of pressure to calculate for the height climbed by the mountain hiker. The change of pressure is given by
p = rho * g * h, where p is the change of pressure, rho is the air density, g is the acceleration due to gravity, and h is the height.
Using the conversion 1 mbar = 100 Pa,
(930 - 780)(100) = (1.20)(9.80)h
15000 = 1.20*9.80*h
h = 1.28 km
Answer:
correct answer is Precipitous vaginal delivery
Explanation:
given data
cervix dilated = 4 cm
effaced = 100%
delivery = 5 minutes later
solution
correct answer is Precipitous vaginal delivery because precipitous take delivery time less than = 3 hours
A multipara progress at rate 1.5 cm of dilation per hour
and it is progress for 10 cm for the deliver and birth averages approx 20 minute
so here correct answer is Precipitous vaginal delivery
Answer:
819.78 m
Explanation:
<u>Given:</u>
- OA = range of initial position of the airplane from the point of observation = 375 m
- OB = range of the final position of the airplane from the point of observation = 797 m
= angle of the initial position vector from the observation point = 
= angle of the final position vector from the observation point = 
= displacement vector from initial position to the final position
A diagram has been attached with the solution in order to clearly show the position of the plane.

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

The magnitude of the displacement vector = 
Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.
Answer:
Technician B is correct
Explanation:
An oxygen sensor will generate about 1.0 volts when the fuel mixture is rich and there is little unburned oxygen in the exhaust. When the mixture is lean, the sensor's output voltage will drop down to about 0.1 volts.
An o2 sensor cannot accurately measure how rich or how well an exhaust system is.
Therefore, Technician B is correct.