You just said that the object is "floating".
(As soon as you said that, a picture of a duck flashed through my mind. But then I knew right away that the duck could not be an accurate representation of the situation you're describing. 340 N would be <u><em>some duck</em></u> ... about 76 pounds ... and that duck would have been caught and eaten a long time ago. I mean ... what could a 76-pound duck do ? Could it fly away ? Could it run away ? ? Not likely.)
So it's not a duck, but whatever it is, it's just sitting there on the water, floating. What's important is that it's <u><em>not accelerating</em></u> up or down. THAT tells us that the vertical forces on it are balanced so that there's NO NET vertical force on it at all.
What are the vertical forces on it ? There's gravity, pulling it DOWN with a force of 340 N, and there's buoyancy, pushing it UP. The SUM of those two forces must be <em>zero</em> ... otherwise the object would be accelerating up or down.
It's not. So (gravity) + (buoyancy) must add up to zero.
The buoyant force on the object is <em>340 N UPward.</em>
Answer:
8.9 units
Explanation:
The magnitude of a 3-D vector B can be calculated by using the formula:
where 
are the x, y and z components of the vector, respectively.
For the vector in the problem:
Substituting into the equation, we find the magnitude of B:
So, the magnitude of B is 8.9 units.
Explanation:
I remember that notation! The expression
is the 1st law of thermodynamics and it refers to the heat supplied to the system dQ which is also a change in its internal energy dU. The first term is the <u>partial</u> derivative of the internal energy U with respect to temperature T while the volume V is kept constant, as denoted by the subscript V. The 2nd term is similar but this time, temperature is kept constant while its volume partial derivative is being taken.
Ah, memories!
Answer:
No it's not true electric grow from Positive terminal to negative terminal
Answer:
KE2 = 2 KE1
1/2 M V2^2 = 2 * (1/2 M V1^2)
V2^2 = 2 V1^2
V2 = V1
Since momentum = M V the momentum increases by
