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mamaluj [8]
3 years ago
13

How many moles are in 400 ml of hydrogen

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

403.176

Explanation:

I hope that the right answer.

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For the balanced equation shown below, how many moles of o2 will react with 0.3020 moles of co2? 2c2h5oh + 6o2 → 4co2 + 6h2o que
MariettaO [177]
The balanced reaction for combustion is as follows ;
2C₂H₅OH + 6O₂ ---> 4CO₂ + 6H₂O
the stoichiometry of C₂H₅OH to O₂ is 2:6
that means 2 mol of C₂H₅OH reacts with 6 mol of O₂.
when 1 mol of C₂H₅OH reacts with 6/2 mol of O₂,
then 0.3020 mol of C₂H₅OH reacts with - 6/2 x 0.3020
therefore number of O₂ moles reacted = 0.91 mol
6 0
3 years ago
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Which polymer is a biopolymer?
kodGreya [7K]
Polylactic acid is the correct answer
6 0
2 years ago
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Write the equilibrium constant expression for the reaction below.
kodGreya [7K]

Answer:

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

Explanation:

The equilibrium constant indicates the % of the yield reaction and can shows where the reaction is going to be equilibrated.

It works with molar concentrations on the equilibrium and it does not consider the solids compounds

Kc also can be modified by the time of the reaction.

This reaction is:

CS₂ (g) + 4 H₂O(g) ⇌ CH₄ (g) + 2H₂S (g)

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

8 0
2 years ago
Were you in ms.secrihrst class in dutchtown middle.
IrinaVladis [17]

NO, why though this is a simple question lol!

4 0
3 years ago
Find the percentage composition of each element in the compound having 9.8 grams of nitrogen,0.7 grams of hydrogen and 33.6 gram
prisoha [69]

Answer: The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

Explanation:

Percentage composition is defined as the ratio of mass of substance to the total mass in terms of percentage.

Percentage composition=\frac{\text {mass of the element}}{\text {Total mass of the substance}}\times 100\%

a) {\text {percentage composition of nitrogen}}=\frac{\text {mass of nitrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of nitrogen}}=\frac{9.8g}{9.8+0.7+33.6}\times 100\%=22.2\%

b) {\text {percentage composition of hydrogen}}=\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of hydrogen}}=\frac{0.7}{9.8+0.7+33.6}\times 100\%=1.59\%

c) {\text {percentage composition of oxygen}}=\frac{\text {mass of oxygen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of oxygen}}=\frac{33.6}{9.8+0.7+33.6}\times 100\%=76.2\%

The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

4 0
3 years ago
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