<h2>
Answer:</h2>
- Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s).
<u>Moles Cu present</u> = 100g Cu x 1 mol Cu/63.55g
= 1.574moles Cu
<u>Mass of Ag produced</u> = 1.574mol Cu x 2mol Ag / 1mol Cu x 107.9g Ag/mol Ag
= 340.g Ag
Brownian motion is a <span>movement of microscopic particles in a fluid, as a result of continuous bombardment from molecules of the surrounding medium.
As colloid is a fluid in which particles move due to bombardment from molecules, they exhibit Brownian motion
Hope this helps!</span>
I believe so because the oxygen goes from 0 to 2- and magnesium goes to 2+ so the oxygen is being reduced and the magnesium is begin oxidized.
Answer:
6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Given:
Concentration is decreased to 1.56 % which means that 0.0156 of is decomposed. So,
![\frac {[A_t]}{[A_0]}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D)
= 0.0156
Thus,
![\frac {[A_t]}{[A_0]}=e^{-k\times t}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%3De%5E%7B-k%5Ctimes%20t%7D)
kt = 4.1604
The expression for the half life is:-
Half life = 15.0 hours
Where, k is rate constant
So,
<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>
Glass is VERY unreactive. meaning that the chemical won't destroy the chemical
