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Kazeer [188]
4 years ago
15

Which statement defines rate-determining step in a chemical reaction?

Chemistry
2 answers:
seropon [69]4 years ago
6 0
A) T<span>he slowest step that determines the speed (rate) of the overall reaction</span>
PilotLPTM [1.2K]4 years ago
4 0
The correct response would be A. The slowest step that determines the speed(rate) of the overall reaction.
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What are the major specials presents in a solution of a strong acid like HCl
lubasha [3.4K]

Answer:

hydrogen ions (H⁺) and chloride ions (Cl⁻)

Explanation:

Hydrochloric acid (HCl) is a strong acid. That means that the compound dissociates completely into ions when is dissolved in water, as follows:

HCl → H⁺ + Cl⁻

The equilibrium is completely shifted to the right side (products). Thus, it is considered that the concentration of the non-dissociated compound (HCl) is negligible, and the major specials present in the solution are the hydrogen ions (H⁺) and chloride ions (Cl⁻).

4 0
3 years ago
Label each molecule with the name of its shape. click on the 3d models to rotate the molecules.
SIZIF [17.4K]
??? There's no image?..
6 0
4 years ago
Which mixture is heterogeneous?
raketka [301]
I guess it is D, bc heterogeneous means a mixture that’s not uniform in structure
3 0
3 years ago
In standardizing the solution of aqueous sodium hydroxide, a chemist overshoots the end point and adds too much naoh(aq). would
irinina [24]

Answer: Concentration of NaOH calculated will be underestimated.

Explanation:

End point is an observational point , which tells us about the completion of reaction between the titrant (solution in burette) and titre(solution in conical flask) in titration experiment.

In this case , NaOH is titrant whose concentration is unknown.

M_1=\text{molarity of titre} , M_2=\text{molarity of NaOH}

V_1=\text{volume of titre} , V_2=\text{volume of NaOH}

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}....(1)

According to question a chemist overshoots the end point and adds to much of NaOH solution, which means increase in the value of V_2.

Then the value of M_2 in equation (1), will get lowered , which means that the concentration of NaOH was lower than that of the actual value. Hence underestimated concentration of NaOH.




8 0
3 years ago
Can someone help me with this molar mass problem?[It’s the last one]
quester [9]

Answer:

54.18 \times 10^{23} \ moles in 3 mole of  Al_2(SO_4)_3

Explanation:

It is clear that in the given 1\ mole of Al_2(SO_4)_3 have 3\ ions of SO_4^2^-

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Since 1 ion of anything is equivalent to 6.02\times10^{23} \ moles

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Which is equivalent to 9 \times6.02\times10^{23}=54.18\times10^{23} \ moles

Thus 3 moles of  Al_2(SO_4)_3 gives 54.18\times10^{23} \ moles of  SO_4^2^-.

5 0
4 years ago
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