Answer:
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
Explanation:
Moles of glucose = 
According to the reaction, 1 mol of gluocse gives 2 moles of ethanol.
Then 2.833 moles of glucose will give :
Mass of 5.667 moles of an ethanol :
5.667 mol × 46 g/mol = 260.682 g
Volume of ethanol = V
Density of the ethanol = 0.789 g/mL
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
Answer:
The volume of the gas at 100°C is 4.6189 liters.
Explanation:
For this problem we are going to use Charles' law. Charles' law states that the volume is directly proportional to temperature given that the pressure is constant. In order to use the equation, the unit of temperature should be in Kelvin.
The working equation is:
=
where V1 and T1 are the initial volume and temperature while V2 and T2 are the final conditions.
Let us convert first the temperatures before solving for the final volume.
To convert Celsius to Kelvin just add 273.15 to temperature in Celsius.
50°C + 273.15 = 323.15 K
100°C + 273.15 = 373.15 K
Solving for the final volume:
V₂ =
V₂ =
V₂ = 4.6189 L
Therefore the final volume of the gas at 100°C is 4.6189 L.
Explanation:
Hbr is the answer when I work it out that’s what I got.
Answer:
This is because the carbon dioxide gas that dissolved in the water is not very soluble. ... After the citric acid solution and baking soda react, carbon dioxide gas is formed, along with other products.
