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1 year ago

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Technologies that could help reduce the damage from a tsunami

1 answer:

Olin [163]1 year ago

8 0

Commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.

<h3>What are the technologies that could help reduce the damage from a tsunami?</h3>

Commonly seawalls are used for preventing damage from tsunamis. There is a network which is used for detecting the earthquake and tsunami and that network is known as Seismological network. This network helps the people to know about the earthquakes and tsunamis and reduces the damages of earthquakes and tsunamis.

The engineers also design a special type of special buoys which is also known as floating devices, these devices are placed near the coastal areas from where the tsunamis can be detected easily.

So we can conclude that commonly the sea walls are used for preventing damage from tsunami. A special type of device is also used for detecting the tsunami called floating device.

Learn more about Tsunami here: brainly.com/question/11687903

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The volume of the earth is approximately 1.08326x10 to the 12th power km to the 3rd power. How many liters is this

mafiozo [28]

Here, we are required to determine the volume of the earth which is 1.08326 × 10¹² km³ in liters.

<em>The volume of the earth is approximately</em>,

, 1.08326 × 10²⁴ liters

By conversion factors;

<em>1dm³ = 1liter</em>
However; <em>1km = 10000dm = 10⁴ </em><em>dm</em>
Therefore, 1km³ = (10⁴)³ dm³.

Consequently, 1km³ = 10¹²dm³ = 10¹²liters.

The conversion factor from 1km³ to liters is therefore, c.f = 10¹²liters/km³

Therefore, the volume of the earth which is approximately, 1.08326 × 10¹² km³ can be expressed in liters as;

<em>1.08326 × 10¹² km³ × 10¹²liters/km³ </em>

The volume of the earth is approximately,

1.08326 × 10²⁴ liters.

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A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?

zhuklara [117]

Answer:

16.56g

Explanation:

6*2.76=16.56...

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3 years ago

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Ivanshal [37]

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In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of $NH_3$ = 100 g

Molar mass of $NH_3$ = 27 g/mole

Molar mass of $N_2$ = 28 g/mole

First we have to calculate moles of $NH_3$ .

$\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles$

The given balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given reaction, we conclude that

2 moles of $NH_3$ produced from 1 mole of $N_2$

3.7 moles of $NH_3$ produced from $\frac{1mole}{2mole}\times 3.7mole=1.85moles$ of $N_2$

Now we have to calculate the mass of $N_2$ .

Mass of $N_2$ = Moles of $N_2$ × Molar mass of $N_2$

Mass of $N_2$ = 1.85 mole × 28 g/mole = 51.8 g

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3 years ago

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