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vladimir2022 [97]
3 years ago
9

How do I find the area for this?

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer: when u doing area know you are multiplying hope i help

Step-by-step explanation:

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Can someone please tell me the aswer​
Artist 52 [7]

Answer:

2x-2+3x

Step-by-step explanation:

2x-2+3x

combine like terms (2x + 3x = 5x)

So 2x-2+3x = 5x-2

3 0
3 years ago
Question in attachment
sdas [7]

Answer:

a₁ = 6

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1}

where a₁ is the first term and r the common ratio

Here S_{8} = 1530 and r = 2, thus

\frac{a_{1}(2^{8}-1)  }{2-1} = 1530 , that is

a₁ (256 - 1) = 1530

255a₁ = 1530 ( divide both sides by 255 )

a₁ = 6

8 0
3 years ago
What is the area of 4.5 and 5.5cm and 20cm
amm1812

Answer:

6.8

Step-by-step explanation:

8 0
3 years ago
Select the correct answer from each drop-down menu.
serious [3.7K]

Answer:

Center: (4,8)

Radius: 2.5

Equation: (x-4)^2+(y-8)^2=6.25

Step-by-step explanation:

It was given that; the endpoints of the longest chord on a circle are (4, 5.5) and (4, 10.5).

Note that the longest chord is the diameter;

The midpoint of the ends of the diameter gives us the center;

Use the midpoint formula;

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

The center is at; (\frac{4+4)}{2} ,\frac{5.5+10.5}{2}=(4,8)

To find the radius, use the distance formula to find the distance from the center to one of the endpoints.

The distance formula is;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(4-4)^2+(10.5-8)^2}

r=\sqrt{0^2+(2.5)^2}

r=\sqrt{0^2+(2.5)^2}=2.5

The equation of the circle in standard form is given by;

(x-h)^2+(y-k)^2=r^2

We substitute the center and the radius into the formula to get;

(x-4)^2+(y-8)^2=2.5^2

(x-4)^2+(y-8)^2=6.25

6 0
3 years ago
There are 27 performances in a dance recital. The ratio of hip hop to ballet is 5:4.
Aloiza [94]

Answer:

15 hip hop performances

12 ballet performances

Step-by-step explanation:

5:4 (multiply by 3)

15:12

6 0
3 years ago
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