The answer is B!!! Statement B is not true!
=<span><span><span><span><span><span><span><span><span>148.413159d</span><span>f2</span></span>i</span>l</span><span>o4</span></span>s</span>y</span>+<span><span>a<span>l2</span></span><span>o3</span></span></span>+<span>a<span>l is the answer and have a nice day :)</span></span></span>
Answer:
pH of the buffer is 10.10
Explanation:
trimethylamine is a weak base that, in presence with its conjugate base, trimethylammonium ion, produce a buffer.
To determine the pH of the buffer we use H-H equation for weak bases:
pOH = pKb + log [Conjugate acid] / [Weak base]
<em>pKb is -log Kb = 4.20</em>
<em />
pOH = 4.20 + log [N(CH₃)₃] / [NH(CH₃)₃]
Replacing the concentrations of the problem:
pOH = 4.20 + log [0.20M] / [0.40M]
pOH = 3.90
As pH = 14 -pOH
<h3>pH of the buffer is 10.10</h3>
<em />
Answer:
the 2p5 should have filled up one more so it would be 2p6 ...which assuming it's not an excited electron?
Answer:
its c I truly believe that it is c
Explanation:
