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IgorLugansk [536]
3 years ago
14

Who know the answer

Chemistry
1 answer:
bekas [8.4K]3 years ago
6 0

First, let's explain the variables. F means force, m means mass, and a means acceleration. F is measured in Newotns [N], mass is measured in kilograms [kg], and acceleration in measured in meters per squared second [m/s²].

Now let's mover on the first problem.

Given

m = 1000 kg

a = 3 m/s²

According to the second law of Newton, the force is equal to the acceleration multiplied by the mass.

F = am\\F = 3 * 1000\\F = 3000 N

The answer is 3000 N.

The second problem is smiliar.

Given

m = 70 kg

F = 250 N

We use the same formula from before, and use a bit of algebra to adapat it to our needs.

F = ma\\\frac{F}{m} = a\\a = \frac{F}{m}\\a = \frac{250}{70} \\a = 24\frac{1}{7} m/s^{2}

The answer is 24 1/7 s/m^2.

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Calculate the value of ka for acetylsalicylic acid
lianna [129]

The value of Ka for acetylsalicylic acid will be calculated as Ka=(x+a)²/x.

<h3>What is Ka?</h3>

Ka is known by the name of acid dissociation constant and for weak acid HA at equilibrium Ka will be calculated as:

Ka = [H⁺][A⁻] / [HA]

Chemical equation with ICE table for the acetylsalicylic acid will be shown as:

                  C₉H₈O₄(aq)  +  H₂O(l)  ⇄  C₉H₇O₄(aq)  +  H₃O⁺(aq)

Initial:                 x                                        0                     0

Change:            -a                                        +a                   +a

Equilibrium:      x-a                                      x+a                 x+a

So, Ka for acetylsalicylic acid will be calculated by putting values on the above equation as:

Ka = [x+a][x+a] / [x-a]

Value of a is negligible as compared to the value of x of acetylsalicylic acid so the term x-a becomes x and equation will be written as:

Ka = (x+a)² / x

By knowing the all values of concentration we can calculate the value of Ka.

Hence Ka value for acetylsalicylic acid will be calculated by using the formula as Ka = (x+a)² / x.

To know more about Ka, visit the below link:

brainly.com/question/26998

#SPJ4

5 0
2 years ago
Answer ASAP plzzz ! Will give Brainliest !
vesna_86 [32]

Answer:

27 mL

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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4 years ago
What is an ion in chemistry
Inga [223]
Its an atom, or molecule, [in which] the complete amount of electrons isn't equal to the complete amount of protons. (Giving the atom/molecule a positive or negative electrical charge). 

If this is incorrect- I'm sorry! ^^;


4 0
3 years ago
Sort the steps in the scientific method.
saw5 [17]

Answer:

  1. Interpretation
  2. Investigation
  3. Hypothesis
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5 0
3 years ago
The common titanium alloy known as T-64 has a composition of 90 weight% titanium 6 wt% aluminum and 4 wt% vanadium. Calculate th
Anna007 [38]

Explanation:

Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.

Mass of titanium = 90 g

Moles of titanium = \frac{90 g}{47.87 g/mol}=1.8800 mol

Total number of atoms of titanium ,a_t=1.8800 mol\times N_A

Mass of aluminum = 6 g

Moles of aluminium = \frac{6 g}{26.98 g/mol}=0.2223 mol

Total number of atoms of aluminium,a_a=0.2223 mol\times N_A

Mass of vanadium  = 4 g

Moles of vanadium= \frac{4 g}{50.94 g/mol}=0.0785 mol

Total number of atoms of vanadiuma_v=0.0785 mol\times N_A

Total number of atoms in an alloy = a_t+a_a+a_v

Atomic percentage:

Atomic\%=\frac{\text{total atoms of element}}{\text{Total atoms in alloy}}\times 100

Atomic percentage of titanium:

:\frac{a_t}{a_t+a_a+a_v}\times 100=\frac{1.8800 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=86.20\%

Atomic percentage of Aluminium:

:\frac{a_a}{a_t+a_a+a_v}\times 100=\frac{0.2223 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=10.19\%

Atomic percentage of vanadium

:\frac{a_v}{a_t+a_a+a_v}\times 100=\frac{0.0785 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=3.59\%

6 0
4 years ago
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