The value of Ka for acetylsalicylic acid will be calculated as Ka=(x+a)²/x.
<h3>What is Ka?</h3>
Ka is known by the name of acid dissociation constant and for weak acid HA at equilibrium Ka will be calculated as:
Ka = [H⁺][A⁻] / [HA]
Chemical equation with ICE table for the acetylsalicylic acid will be shown as:
C₉H₈O₄(aq) + H₂O(l) ⇄ C₉H₇O₄(aq) + H₃O⁺(aq)
Initial: x 0 0
Change: -a +a +a
Equilibrium: x-a x+a x+a
So, Ka for acetylsalicylic acid will be calculated by putting values on the above equation as:
Ka = [x+a][x+a] / [x-a]
Value of a is negligible as compared to the value of x of acetylsalicylic acid so the term x-a becomes x and equation will be written as:
Ka = (x+a)² / x
By knowing the all values of concentration we can calculate the value of Ka.
Hence Ka value for acetylsalicylic acid will be calculated by using the formula as Ka = (x+a)² / x.
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Answer:
27 mL
Explanation:
Please see the step-by-step solution in the picture attached below.
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Its an atom, or molecule, [in which] the complete amount of electrons isn't equal to the complete amount of protons. (Giving the atom/molecule a positive or negative electrical charge).
If this is incorrect- I'm sorry! ^^;
Explanation:
Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.
Mass of titanium = 90 g
Moles of titanium = 
Total number of atoms of titanium ,
Mass of aluminum = 6 g
Moles of aluminium = 
Total number of atoms of aluminium,
Mass of vanadium = 4 g
Moles of vanadium= 
Total number of atoms of vanadium
Total number of atoms in an alloy = 
Atomic percentage:

Atomic percentage of titanium:
:
Atomic percentage of Aluminium:
:
Atomic percentage of vanadium
: