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Natali5045456 [20]
4 years ago
10

What is the correct not sure if I'm coming up with the correct one

Mathematics
1 answer:
Gennadij [26K]4 years ago
3 0
I think it's C but I might not be right
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Matt Bonner has 8 dimes, 9 pennies, and 4 quarters in his pocket. If each coin is equally likely to be pulled out of his pocket
Lesechka [4]

Answer:

B. 0.602%

Step-by-step explanation:

Probability is essentially (# times specific event will occur) / (# times general event will occur). Here, we have a few specific events: draw a quarter, draw a second quarter, draw a penny, and draw another penny. The general event will just be the number of coins there are to choose from.

The probability that the first draw is a quarter will be 4 / (4 + 8 + 9) = 4/21.

Since we've drawn one now, there's only 21 - 1 = 20 total coins left. The probability of drawing a second quarter is: (4 - 1) / (21 - 1) = 3/20.

The probability of drawing a penny is: 9 / (20 - 1) = 9/19.

The probability of drawing a second penny is: (9 - 1) / (19 - 1) = 8/18.

Multiply these four probabilities together:

(4/21) * (3/20) * (9/19) * (8/18) = 864 / 143640 ≈ 0.602%

The answer is B.

8 0
4 years ago
Read 2 more answers
Evaluate.
Whitepunk [10]
<span>35.3529411765 that is the answer


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7 0
4 years ago
Brad's Medicare levy was $1312.50. This was 1.5% of his taxable income.
Arisa [49]

Step-by-step explanation:

$1312.50×1.5%÷100

=20.25 that's taxable income

or

you can say $1312.50- 1.5%

=20.25

3 0
3 years ago
The height of a small rock falling from the top of a 124-ft-tall building with an initial downward velocity of –30 ft/sec is mod
Contact [7]

Answer:

Option 3.

Step-by-step explanation:

The given function is

h(t)=-16t^2-30t+124

where, h(t) is the height of a small rock falling from the top of a 124-ft-tall building and t is the time in seconds.

It is a downward parabola.

Equate the function equal to 0, to find the time at which the rock touch the ground.

-16t^2-30t+124=0

If ax^2+bx+c=0, the according to the quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Using quadratic formula, we get

t=\dfrac{-(-30)\pm \sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=\dfrac{30+\sqrt{(-30)^2-4(124)(-16)}}{2(-16)},\dfrac{30-\sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=-3.875, 2

Time cannot be negative. So, the rock remain in the air in the interval 0 < t < 2.

Therefore, the correct option is 3.

6 0
3 years ago
Please help and answer all questions from the attachments. Will give brainliest to correct answers from attachments.
Nikitich [7]

Answer:

See attachments

Step-by-step explanation:

Hope this helps.

3 0
3 years ago
Read 2 more answers
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