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kobusy [5.1K]
3 years ago
14

Line segment Z E is the angle bisector of AngleYEX and the perpendicular bisector of Line segment G F. Line segment G X is the a

ngle bisector of AngleYGZ and the perpendicular bisector of Line segment E F. Line segment F Y is the angle bisector of AngleZFX and the perpendicular bisector of Line segment E G. Point A is the intersection of Line segment E Z, Line segment G X, and Line segment F Y.
Triangle G E F has angles with different measures. Point A is at the center. Lines are drawn from the points of the triangle to point A. Lines are drawn from point A to the sides of the triangle to form right angles and line segments A X, A Z, and A Y.
Which must be true?

Point A is the center of the circle that passes through points E, F, and G but is not the center of the circle that passes through points X, Y, and Z.
Point A is the center of the circle that passes through points X, Y, and Z but is not the center of the circle that passes through points E, F, and G.
Point A is the center of the circle that passes through points E, F, and G and the center of the circle that passes through points X, Y, and Z.
Point A is not necessarily the center of the circle that passes through points E, F, and G or the center of the circle that passes through points X, Y, and Z.
Mathematics
1 answer:
notsponge [240]3 years ago
3 0

i dont l know bro try getting close to God tho

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Answer this math question pls I'm in a rush
777dan777 [17]

Answer:

61/18

Step-by-step explanation:

Make the mixed fraction an improper fraction first. So instead of 1 1/3, it'll be 4/3.

Now in a rectangular prism, there's two of each congruent sides (three pairs in total).

You'll need to multiply (4/3)(3/4) by 2 because there's two of them.

This gives you (1)(2) which equals 2.

Next, take another set --> (4/3)(1/3)(2) again because there's two of them.

This gives you (4/9)(2) which equals 8/9.

Last, take the last set --> (3/4)(1/3)(2)

This gives you (1/4)(2) which equals 1/2.

Now that you have all the areas of the rectangles, add them all together.

2+8/9+1/2 which equals 61/18 inches squared.

6 0
4 years ago
I need help with question B)
Lady bird [3.3K]

Answer:

i cant see the graph, how do you expect us to awser you

3 0
3 years ago
Simplify 3a^2b^2x2ab+6a^3b^2
ira [324]

3 {a}^{2} \times  {b}^{2} \times 2ab + 6 {a}^{3} \times  {b}^{2} =

6 {a}^{3} {b}^{3} + 6 {a}^{3} {b}^{2} =

Factoring 6a^3 b^2

6 {a}^{3} {b}^{2}(b + 1)

_________________________________

I think this is the correct answer.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
True or False? A circle could be circumscribed about the quadrilateral below.
Luba_88 [7]

Answer:

It is False!!

NO MATTER WHICH IS THE QUADRILATERAL IT CANT BE DONE.

PLEASE MARK AS BRAINLIEST IF I AM CORRECT

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Answer:

1/9

Step-by-step explanation:

4 0
3 years ago
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