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Alborosie
3 years ago
8

What is the surface area of the hemishpere? 32 m

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
5 0

Answer:

The surface area of a sphere of radius r is 4 π r2. Half of this is 2 π r2. If this is what is meant by the surface area of a hemisphere then 2 π r2 = 1062.

Step-by-step explanation:

Darya [45]3 years ago
4 0

Answer:

K = (2πr2) + (πr2) = 3πr

Step-by-step explanation:

K = (2πr2) + (πr2) = 3πr Heres something that might help.

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Avery’s water bottle holds 300 milliliter. Dashawn’s container holds 3/4 as much water. How many milliliters do both containers
Nady [450]

Answer:

Both containers hold 225 ml.

Step-by-step explanation:

300/4 =75 so 1/4 is equal to 75 mL


300-75=225mL


Dashawn's water bottle holds 225mL

Hope this helps! :)


<h3>CloutAnswers</h3>
8 0
3 years ago
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Step-by-step explanation:

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Simply the following ratio 1000:540:780
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3 0
3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
2 years ago
If g(x) = x^2 + 2, find g(3). <br><br> A. 9 <br> B. 8 <br> C. 11 <br> D. 6
TiliK225 [7]
Replace x=3 so 3 squared is 9 and when u add 2 it equals 11
8 0
3 years ago
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