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3 years ago

What is the answer to these questions?

Mathematics

1 answer:

raketka [301]3 years ago

5 0

Answer:

The answer to the first question is: 9 4/21

The answer to the second question is: B.) 24 14/27

I hope this helps you! :D

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Help!! Which is the correct answer?

kakasveta [241]

7300-5500=1800 needs to come from salespeople. To make at least 7300, the salespeople need to make at least 1800, which means:
300 x number of people >= 1800
Number of people >= 6
C is correct

3 0

3 years ago

The bill for dinner was $34. You left $50 to pay for the meal and tip the server. What percent of the meal did you leave as a ti

9966 [12]

Answer:

Step-by-step explanation:

$50 - 34 = 16$

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3 years ago

A town has a population of 17000 and grows at 3% every year. What will be the population after 7 years, to the nearest whole num

Pepsi [2]

Answer:

122570

(17000*1.03)7

4 0

3 years ago

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Suppose a large shipment of microwave ovens contained 12% defectives. If a sample of size 474 is selected, what is the probabili

melisa1 [442]

Answer:

$P(\hat p>0.14)$

And using the z score given by:

$z = \frac{\hat p -\mu_p}{\sigma_p}$

Where:

$\mu_{\hat p} = 0.12$

$\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149$

If we find the z score for $\hat p =0.14$ we got:

$z = \frac{0.14-0.12}{0.0149}= 1.340$

So we want to find this probability:

$P(z>1.340)$

And using the complement rule and the normal standard distribution and excel we got:

$P(Z>1.340) = 1-P(Z$

Step-by-step explanation:

For this case we have the proportion of interest given $p =0.12$ . And we have a sample size selected n = 474

The distribution of $\hat p$ is given by:

$\hat p \sim N (p , \sqrt{\frac{p(1-p)}{n}})$

We want to find this probability:

$P(\hat p>0.14)$

And using the z score given by:

$z = \frac{\hat p -\mu_p}{\sigma_p}$

Where:

$\mu_{\hat p} = 0.12$

$\sigma_{\hat p}= \sqrt{\frac{0.12*(1-0.12)}{474}}= 0.0149$

If we find the z score for $\hat p =0.14$ we got:

$z = \frac{0.14-0.12}{0.0149}= 1.340$

So we want to find this probability:

$P(z>1.340)$

And using the complement rule and the normal standard distribution and excel we got:

$P(Z>1.340) = 1-P(Z$

4 0

4 years ago

Write in standard form 4,000,000+3,000+50+2

Andreas93 [3]

4,003,052 is the answer to the problem

7 0

3 years ago

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