The answer is Infinate Solutions I believe we are working on these types of equations in school rn
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,
As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then 
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.
Answer:
-54, 162, -486
Step-by-step explanation:
You multiply the number in front by -3.
2*-3=-6
-6*-3=18
18*-3=-54
-54*-3=162
162*-3=-486
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Answer:
abc to rqp is the right ans
Answer:
(2, 1)
Step-by-step explanation:
To solve by substitution, we solve one equation for one of its variables and then substitute the solved value for that variable into the other equation. Because this system of equations already has one solved for the variable, this makes our job much easier. We only need to implement the solved value for y into the other equation and solve for x.
y = 6x - 11
-2x - 3(6x - 11) = -7 Distribute.
-2x - 18x + 33 = -7 Combine like terms.
-20x + 33 = -7 Subtract 33 from both sides of the equation.
-20x = -40 Divide by -20 on both sides of the equation.
x = 2
Then, with this value, we will place it into the equation that was already solved for y in order to get a definite value for y.
y = 6(2) - 11
y = 12 - 11
y = 1
Using this information, the coordinate pair for this equation (the point of intersection between the two lines) is (2, 1).
