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AleksandrR [38]
3 years ago
15

Solve for k

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

When solving equations the goal is to get the variable by itself so

4.5+1.5k=18-3k (first step is to subtract 4.5 from each side)

1.5k=13.5-3k (4.5-4.5=0, 18-4.5=13.5) (Next is to add 3k to each side)

4.5k=13.5 (1.5k+3k=4.5k, -3k+3k=0) (Last you divide both sides by 4.5)

k=3 (4.5/4.5=1, 13.5/4.5=3)

k=3

Hope this helps ;)

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Allisa [31]

For line B to AC:  y - 6 = (1/3)(x - 4);  y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14

For line A to BC:  y - 6 = (-1)(x - 0);  y - 6 = -x, so y + x = 6

Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:

(3y - x = 14) + (y + x = 6) =>  4y = 20, y = +5;  Substitute this into y + x = 6:  5 + x = 6, x = +1

<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>

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3 years ago
What is the solution to the system of equations? HELP
notsponge [240]
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<span>
so the answer is B (the second choice)
(Hope it helped ^_^)




</span></span></span>
4 0
3 years ago
Read 2 more answers
Please anyone help me answer this question am giving the brainliest
DochEvi [55]

Answer:

(-3/2x+1) + (3/x-1)

Step-by-step explanation:

Dont put the answer in parenthesis, I just did that to seprate it so it was easier to read. If you need it to be put in word form for it to be easier for you to understand, its "negative three divided by two x plus one, plus 3 divided by x minus 1"

First, rewrite the expression as 3x+6/2x^2+x-2x-1

Then, factor the expression, 3x+6/x*(2x+1)-(2x+1) (*=multiply)

Then, write a new fraction for each factor in the denominator, then write a new fraction, 3x+6/(2x+1)*(x-1) to (A)/2x+1 + B/x-1)

Then write terms in the numerators, for now we will use A and B.

Now we set the sum of the fractions equal to the original fraction.

3x+6/(2x+1)*(x-1) = A)/2x+1 + B/x-1).

Then reorder and group the terms, giving you 3x+6=(A+2B)x+(-A+B).

Now equate the coefficiants, {6= -A+B, 3= A+2B

Then substitute back, (A, B)=(-3, 3)

Now finally, just rewrite the fraction. (-3/2x+1) + (3/x-1)

Hope this helps! Sorry its kind of long.

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To solve these kinds of problems, it is necessary to isolate x:

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