Resistance of a lightbulb is 240.8 ohm
Given:
Power = 120 W
Frequency = 60.0-Hz
Voltage = 170 V
To Find:
Resistance of a lightbulb
Solution: The electrical resistance of a circuit is the ratio between the voltage applied to the current flowing through it. Rearranging the above relation, R = V I. The unit of electrical resistance is ohms.
The resistance of the light bulb is given by the formula, R=V²/P
R = (170)^2/120
R = 240.8 ohm
Hence, the resistance of light bulb is R = 240.8 ohm
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I believe the answer is C
Answer:
1) 65 m
2) 40 m/s downward
Explanation:
Using for both questions the kinematic equation
v² = u² + 2as
and ignoring air resistance.
1) h = 60 + √(20²/(2(9.8))) = 64.51753...
2) v = √(20² + 2(9.8)(60)) = 39.69886...
The answer is to the ground.
Gravity refers to the force that holds together the universe. On Earth, the gravity attempts to change the velocity of all the objects on the Earth's surface toward the ground at a rate of 9.8 meters per second squared according to Galileo.
Answer:
Find a recipient that you can put the object completely inside, and fill this recipient with water. After, you put the irregular solid you want to measure the volume inside, and the water will spill out the recipient. So you take the water that spilled out and uses a graduated recipient to measure the volume of water. The volume of the solid will be exactly the same volume of water that spilled of the first recipient