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3 years ago

6

A student eats a candy bar that contains 1.57 x 106 J of energy. If the student has a mass of 81.8 kg, how high will he have to

climb a ladder to completely offset the energy contained in the candy bar?

1 answer:

gogolik [260]3 years ago

6 0

Answer:abb

Explanation:bsjsnd

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What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a<br> velocity of 3.0 m/s?

Sav [38]

46.6666 that is the mass number

Explanation:

14 divided 3.0

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2 years ago

Un acróbata de 60.0 kg está unido a un cordón de bungee con un resorte de 10.0 m de longitud . Salta de un puente que abarca un

Ede4ka [16]

Answer:

What kind of languege is this please?

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2 years ago

Good morning! can someone please answer this, ill give you brainliest and your earning 50 points.

tatyana61 [14]

Answer:

With the exception of natural gas fossil fuel energies have seen an overall decrease since year 2000.

Explanation:

Just observe the graph

The Fossil fuels include-Petroleum ,coal and natural gases.

The graph of these goes fastly up during 20th century but ,then it stabled at the peak then has not shown any solid increase .
Observe other energy sources graph ,nuclear energy etc have shown quite speedy increase .

Option C is correct

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2 years ago

An object in free fall is dropped from a building. Its starting velocity is 0 m/s. Ignoring the effects of air resistance, what

Amanda [17]

Answer:

30m/s^2

Explanation:

Acceleration=Final Velocity-Initial Velocity/Time

10m/s^2= Final Velocity-0m/s/3

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2 years ago

The electromagnetic wave that delivers a cellular phone callto

spin [16.1K]

Answer:

$E=2.41\cdot 10^{-5} J$

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

$I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}}$ (1)

c is the speed of light (3*10⁸ m/s)
μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
B₀ is the magnetic field

$I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}$

$I_{average}=2.68\cdot 10^{-6} W/m^{2}$

Now, let's define the relationship between power (P) and average intensity (I).

$I_{average}=\frac{P}{A}$

P is the power
A is the area crossed

So we can calculate the power.

$P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W$

Finally, energy is the product of P times time, so:

$E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J$

I hope it helps you!

5 0

2 years ago