Answer:
Approximately .
Explanation:
The formula for the kinetic energy of an object is:
,
where
- is the mass of that object, and
- is the speed of that object.
Important: Joule () is the standard unit for energy. The formula for requires two inputs: mass and speed. The standard unit of mass is while the standard unit for speed is . If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,
Convert the unit of the arrow's mass to standard unit:
.
Initial of this arrow:
.
That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:
.
Answer:
v = 2917.35 m/s
Explanation:
let Fc be the centripetal force avting on the satelite , Fg is the gravitational force between mars and the satelite, m is the mass of the satelite and M is the mass of mars.
at any point in the orbit the forces acting on the satelite are balanced such that:
Fc = Fg
mv^2/r = GmM/r^2
v^2 = GM/r
v = \sqrt{GM/r}
= \sqrt{(6.6708×10^-11)(6.38×10^23)/(3.38×10^6 + 1.62×10^6)}
= 2917.35 m/s
Therefore, the orbital velocity of the satelite orbiting mars is 2917.35 m/s.
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Answer:
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Answer:
3.1 × 10^- 7 m and 2.1 × 10^-7 m
Explanation:
First we must convert each value of energy to Joules by multiplying its value by 1.6 ×10^-19. After that, we can now obtain the wavelength from E= hc/λ
Where;
h= planks constant
c= speed of light
λ= wavelength of light
For 6.0ev;
E= 6.0 × 1.6 ×10^-19
E= 9.6 × 10^-19 J
From
E= hc/λ
λ= hc/E
λ= 6.6 × 10^-34 × 3 × 10^8/9.6 × 10^-19
λ= 2.1 × 10^-7 m
For 4.0 eV
4.0 × 1.6 × 10^-19 = 6.4 × 10^-19 J
E= hc/λ
λ= hc/E
λ= 6.6 × 10^-34 × 3 × 10^8/6.4 × 10^-19
λ= 3.1 × 10^- 7 m