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Firdavs [7]
3 years ago
11

Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821

L · atm/mol · K and 1 atm = 760 torr.) 1.40 x 101 L 1.84 x 10-2 L 1.17 x 102 L 1.54 x 10-1 L
Physics
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

pV=nRT

where we have:

p=792 Torr \cdot \frac{1 atm}{760 Torr} = 1.04 atm is the pressure

V is the volume

n = 4.8 mol is the number of moles

R = 0.0821 L · atm/mol · K is the ideal gas constant

T=37^{\circ}+273 =310 K is the temperature

Solving the equation for V, we find the volume

V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L

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Five locations are marked on the world map. The spot that is prone to hurricane mostly A.

<h3>What is hurricane?</h3>

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2 years ago
1) La longitud del brazo de potencia de una palanca es de 0,0035 hectómetros y la del brazo de resistencia es de 55 centímetros.
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A thin walled spherical shell is rolling on a surface. What
ExtremeBDS [4]

Answer:

=\frac{1/3}{5/6} = 0.4

Explanation:

Moment of inertia of given shell= \frac{2}{3} MR^2

where

M represent sphere mass

R -sphere radius

we know linear speed is given as v = r\omega

translational K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2

rotational K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2

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K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2

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