Question

Given 4.8 moles of a gas at 37 degrees Celsius and at 792 torr, what is the volume of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.) 1.40 x 101 L 1.84 x 10-2 L 1.17 x 102 L 1.54 x 10-1 L

Answer 1

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

$pV=nRT$

where we have:

$p=792 Torr \cdot \frac{1 atm}{760 Torr} = 1.04 atm$ is the pressure

V is the volume

n = 4.8 mol is the number of moles

R = 0.0821 L · atm/mol · K is the ideal gas constant

$T=37^{\circ}+273 =310 K$ is the temperature

Solving the equation for V, we find the volume

$V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L$