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blagie [28]
3 years ago
13

Find the probability of rolling a twelve first and then a three when a pair of dice is rolled twice?

Mathematics
2 answers:
yawa3891 [41]3 years ago
6 0
Total number of possible outcomes = 36

Total number of outcomes with a sum of 12 = 1
{6,6)

Total number of outcomes with a sum of 3 = 2
{1,2}{2,1}

P(12 first, then 3) = (1/36)(2/36) = 1/648

Answer: The probability is 1/648
beks73 [17]3 years ago
4 0

|\Omega|=6^2\cdot6^2=1296\\ |A|=1\cdot2=2\\\\ P(A)=\dfrac{2}{1296}=\dfrac{1}{648}\approx0.2\%

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