Find the probability of rolling a twelve first and then a three when a pair of dice is rolled twice?
2 answers:
Total number of possible outcomes = 36
Total number of outcomes with a sum of 12 = 1
{6,6)
Total number of outcomes with a sum of 3 = 2
{1,2}{2,1}
P(12 first, then 3) = (1/36)(2/36) = 1/648
Answer: The probability is 1/648
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