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2 years ago

How many six-inch by six-inch square tiles are needed to cover a three-foot by two-foot rectangular section of floor?

Mathematics

2 answers:

rusak2 [61]2 years ago

5 0

Answer:

Step-by-step explanation:

vazorg [7]2 years ago

3 0

First let's covert ft to inches:
tiles- 6×6 = 36 sq. in.
floor- 3ft×2ft. = (3×12)×(2×12) = 36×24
= 864 sq. in.
now divide total (floor) by each tile:
864÷36 = 24 tiles

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The equation 2y = 8x represents a proportional relationship. What is the constant of proportionality?

Sphinxa [80]

Answer:

C) 4

Step-by-step explanation:

Given equation:

$2y=8x$

The above equation represents proportional relationship.

To find the constant of proportionality.

Solution:

The equation representing proportional relationship is given by:

$y=kx$

where $k$ represents constant of proportionality.

So, in order to find the value of $k$ for the given proportionality relationship, we will solve for $y$

We have:

$2y=8x$

Solving for $y$

Dividing both sides by 2.

$\frac{2y}{2}=\frac{8x}{2}$

$y=4x$

∴ $k=4$

Thus, the constant of proportionality = 4.

4 0

3 years ago

rove the following statement directly from the definition of rational number. The difference of any two rational numbers is a ra

Umnica [9.8K]

Answer:

Step-by-step explanation:

Question:

Prove the following statement directly from the definitions.

The difference of any two rational numbers is a rational number.

Answer, see attachment for proof.

7 0

2 years ago

The approximate volume of a sphere with a diameter of 10 centimeters is

Alexeev081 [22]

Answer: The volume is approximately 523.6 cm³.

Step-by-step explanation:

The formula for the volume of a sphere is V=4/3(3.14)r³

The radius is 5 cm, the you just have to multiply everything together.

5 0

2 years ago

Find 19/25 of $25,000 A. $2,500 B.$15,000 C.$19,000 D.$1,900

Alla [95]

I am thinking A) Or B) because iPlease chose as best if i am wrong please don't be mad most of my stuff is correct

5 0

2 years ago

Lori creates the following design for a T-shirt.

kakasveta [241]

Solution-

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7

Area of rectangle 1 = 8.68 sq.in

$\Rightarrow FH \times HI=8.68$

$\Rightarrow EB \times HI=8.68$ (∵ sides of the rectangle 2)

$\Rightarrow 2.8 \times HI=8.68$

$\Rightarrow HI=3.1$

Area of Triangle 1 = 6.48 sq.in

$\Rightarrow \frac{1}{2}\times AE \times EG= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48$ (∵ sides of the rectangle 1)

$\Rightarrow EF+3.1= 5.4$

$\Rightarrow EF=2.3$

$\Rightarrow BH=2.3$ (∵ sides of the rectangle 2)

$BC = BH+HI+IC$

$\Rightarrow 11.7= 2.3+3.1+IC$

$\Rightarrow IC=6.3$

The area of Rectangle 2,

$=EB\times BH =2.8\times 2.3=6.44\ sq.in$

The area of Triangle 2,

$\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in$

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in

6 0

2 years ago