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Bingel [31]
3 years ago
14

Write the expression as a single logarithm 2 ln 7 + ln(x+5) - ln(x-3)

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

ln ((49(x+5))/x-3)

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How much total wrapping paper does it take to wrap two gifts: one with the dimensions of 6 cm by 10 cm by 9.5 cm and the other w
zhuklara [117]

Answer:

gift 1:

424 cm^2

570 cm^3

gift 2:

1420.5 cm^2

3622.5 cm^3

Step-by-step explanation:

We have to calculate the surface area of these gifts in order to know the amount of wrapping paper.

The formula for the surface area is:

A = 2*ab + 2*ac + 2*bc

Gift 1:

A = 2*6*10 + 2*6*9.5 + 2*10*9.5

A = 424 cm^2

That means that gift 1 needs 424 cm^2 of wrapping paper

Gift 2:

A = 2*14*17.25 + 2*14*15 + 2*17.25*15

A = 1420.5 cm^2

That means that gift 2 needs 1420.5 cm^2 of wrapping paper

Now, to calculate the cubic centimeters of packaging peanuts, we calculate the volume, the volume has as formula:

V = a*b*c  

Gift 1:

V = 6*10*9.5  

V = 570 cm^3

This means that gift 1 needs 570 cm^3 of packaging peanuts

Gift 2:

V = 14*17.25*15  

V = 3622.5 cm^3

That means that gift 2 needs 3622.5 cm^3 of packaging peanuts

5 0
3 years ago
Explain to another student how to solve the equation.
AveGali [126]

Answer:

Solve for X ( The question I did was an example )

Step-by-step explanation:

To solve and equation like 2x+9=30 you will have to isolate the number with a variable. You need to subtract 9 on both sides for that to happen.

2x=21

Now the next step is to divide. You have to divide to get the answer.

x=21/2

x= 10.5

5 0
2 years ago
What do you call an agarrangment of reciving goods or serviced
olasank [31]
The answer to this is credit.<span />
7 0
3 years ago
Give the discriminant of the equation 0 = −x2+6x−9<br>please answer
Brut [27]

Answer:

x = 3

Steps:

- ( {x}^{2}  - 6x + 9) = 0

-  {(x - 3)}^{2}  = 0

{(x - 3)}^{2}  = 0

x - 3 = 0

There you go!

8 0
3 years ago
Plsss help me !!!!
Yuri [45]

Answer:

The enrollment after 5 years is 10,724

Step-by-step explanation:

Generally, we can have the depreciation formula written as follows;

A = P(1 - r)^t

A is the number of enrollment in after a certain number of years t

P is the initial population which is 13,500

r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045

t = 5 years

Substituting these values, we have it that;

A = 13,500(1-0.045)^5

A = 10,723.84

4 0
2 years ago
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