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4 years ago

If a truck is heading south at a velocity of 90m/s for 10 seconds how far did it travel?

Physics

1 answer:

RoseWind [281]4 years ago

3 0

Answer:

Truck will be at a distance of 720 m

Explanation:

Speed of the truck is given as 90 m/sec

Time for which truck travel t = 10 seconds

We have to find the distance that how much truck travel in 8 sec with speed of 90 m/sec

We know that distance is given by $distance=velocity\times time$

So distance traveled by truck in 8 sec will be equal to $=90\times 8 =720m$

So truck will be at a distance of 720 m

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

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Answer: The mean of the samples is 32.325.

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7 0

4 years ago

Read 2 more answers

A force of 5 N accelerates an object. The object’s mass is 50 g. What is the acceleration of the object? (Formula: F=ma)

goldfiish [28.3K]

Answer:

100 m/s²

Explanation:

First, convert to SI units:

50 g = 0.050 kg

Now plug into the formula:

F = ma

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3 years ago

Read 2 more answers

"if the left-hand mass is 2.3 kg ,what should the right-hand mass be so that it accelerates downslope at 0.64 m/s2?"

VARVARA [1.3K]

m₁ = 2.3 kg 
θ₁ = 70° 
θ₂ = 17° 
g = 9.8 m/s²

->The component of the gravitational force on m₁ that is parallel down the incline is: 
F₁ = m₁ × g × sin(θ₁) 
F₁ = (2.3 kg) × (9.8 m/s²) × sin(70°) = 21.18 N 

->The component of the gravitational force on m₂ that is parallel down the incline is: 
F₂ = m₂ × g × sin(θ₂) 
F₂ = m₂ × (9.8 m/s²) × sin(70°) = m₂ × (2.86 m/s²) 

Then the total mass of the system is:
m = m₁ + m₂ 
m = (2.3 kg) + m₂ 

If it is given that m₂ slides down the incline, then F₂ must be bigger than F₁, 
and so the net force on the system must be:
F = m₂×(2.86 m/s²) - (21.18 N) 

Using Newton's second law, we know that
F = m × a
So if we want the acceleration to be 0.64 m/s², then
m₂×(2.86 m/s²) - (21.18 N) = [(2.3 kg) + m₂] × (0.64 m/s²) 
m₂×(2.86 m/s²) - (21.18 N) = (1.47 N) + m₂×(0.64 m/s²) 
m₂×(2.22 m/s²) = (22.65 N) 
m₂ = 10.2 kg

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4 years ago