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PolarNik [594]
3 years ago
7

Based on the position vs. time graph, which velocity vs. time graph would correspond to the data? A graph with horizontal axis t

ime (seconds) and vertical axis position (meters). A line runs straight upward from 0 seconds 0 minutes. A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A line runs in straight segments from 0 seconds 0 meters per second to 1 second 15 meters per second to 2 seconds 20 meters per second to 4 seconds 20 meters per second to 5 seconds 0 meters per second. A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line begins at 0 seconds 0 meters per second and runs to 5 seconds 5 meters per second. A graph horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line begins at 0 seconds 2 meters per second and runs to 5 seconds 2 meters per second. A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line begins at 0 seconds 10 meters per second and runs to 5 seconds 2 meters per second.
Physics
2 answers:
Dmitriy789 [7]3 years ago
6 0
A graph with horizontal axis time
Anit [1.1K]3 years ago
6 0

Answer:

A,C,E

Explanation:

I shows correct

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A hollow cylinder with an inner radius of 4 mm and an outer radius of 25 mm conducts a 4-A current flowing parallel to the axis
ivann1987 [24]

Answer:

2.1 × 10⁻⁵ T

Explanation:

Given:

Inner radius, r = 4 mm = 0.004 m

Outer radius, R = 25 mm = 0.025 m

Current, I = 4 A

Distance of the point from the center, a = 17 mm = 0.017 m

μ₀ = 4π × 10⁻⁷ T·m/A

Now,

For the hollow cylinder magnetic field (B) is given as:

B=\frac{\mu_0 I(a^2-r^2)\textup{}}{2\pi a(R^2-r^2)\textup{}}

on substituting the respective values, we get

B=\frac{4\pi\times10^{-7}\times4(0.017^2-0.004^2)\textup{}}{2\pi\times0.017(0.025^2-0.004^2)\textup{}}

or

B = 2.1 × 10⁻⁵ T

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A vehicle of known mass accelerates along a straight path. According to Newton's second law of motion, what caused this accelera
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Answer;

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