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PolarNik [594]
3 years ago
7

Based on the position vs. time graph, which velocity vs. time graph would correspond to the data? A graph with horizontal axis t

ime (seconds) and vertical axis position (meters). A line runs straight upward from 0 seconds 0 minutes. A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A line runs in straight segments from 0 seconds 0 meters per second to 1 second 15 meters per second to 2 seconds 20 meters per second to 4 seconds 20 meters per second to 5 seconds 0 meters per second. A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line begins at 0 seconds 0 meters per second and runs to 5 seconds 5 meters per second. A graph horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line begins at 0 seconds 2 meters per second and runs to 5 seconds 2 meters per second. A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line begins at 0 seconds 10 meters per second and runs to 5 seconds 2 meters per second.
Physics
2 answers:
Dmitriy789 [7]3 years ago
6 0
A graph with horizontal axis time
Anit [1.1K]3 years ago
6 0

Answer:

A,C,E

Explanation:

I shows correct

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If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is
leva [86]

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31.831 Hz.

Explanation:

<u>Given:</u>

  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as

\rm y = A\sin(kx -\omega t).

<em>where</em>,

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  • k = wave number of the wave = \dfrac{2\pi }{\lambda}.
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  • \omega = angular frequency of the wave = \rm 2\pi f.
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On comparing the generalized equation with the given equation of the displacement of the wave, we get,

\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,

\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.

It is the required frequency of the wave.

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