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shepuryov [24]
3 years ago
5

A projectile is launched horizontally from a cliff top at 12 m/s. Determine the x-y positions at 1-second intervals. The launch

position is (0 m, 0 m).
Physics
1 answer:
Natalka [10]3 years ago
5 0

The x position will be "12 m" and the y position will be "-4.9 m".

According to the question,

Along x direction, Initial velocity:

  • 12 m/s

Along x direction, Acceleration is:

  • 0

Along y direction, Acceleration is:

  • -10 m/s²

Time,

  • t = 1 second

→ The X coordinate will be:

= 12\times t

= 12\times 1

= 12 \ m

→ The Y coordinate will be:

= -(u_y t+\frac{1}{2}a_y t^2 )

= 0+4.9 t^2

= 4.9 \ t^2

= -4.9\times 1^2

= -4.9 \ m

Thus the above answer is correct.

Learn more:

brainly.com/question/17108357

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