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3 years ago

-9x + 6 = -x + 4 help pls ill give brainliest

Mathematics

2 answers:

tatiyna3 years ago

7 0

Answer: x = 1/4

Step-by-step explanation:

-9x + 6 = -x + 4

+x +x

-8x + 6 = 4

-6 -6

-8x = -2

divide by -8 on both sides

x = 2/8

simplify

garik1379 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

-9x + 6 = -x + 4

-9x + x = 4 - 6

-8x = -2

x = 2/8

x = 1/4

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Step-by-step explanation:

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$\boldsymbol{r}'(t)=\frac{d}{dt}\left(cos\left(2t\right)\right)\:\boldsymbol{i}+\frac{d}{dt}\left(sin\left(2t\right)\right)\:\boldsymbol{j}+\frac{d}{dt}\left(1)\right\:\boldsymbol{k}\\\boldsymbol{r}'(t)=-2\sin \left(2t\right)\boldsymbol{i}+2\cos \left(2t\right)\boldsymbol{j}$

Next , we find the magnitude of derivative of the position vector

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$\boldsymbol{T}}=\frac{\boldsymbol{r}'(t)}{||\boldsymbol{r}'(t)||}$

$\boldsymbol{T}}=\frac{-2\sin \left(2t\right)\boldsymbol{i}+2\cos \left(2t\right)\boldsymbol{j}}{2} =\sin \left(2t\right)+\cos \left(2t\right)$

We need to find the derivative of unit tangent vector

$\boldsymbol{T}'=\frac{d}{dt}(\sin \left(2t\right)\boldsymbol{i}+\cos \left(2t\right)\boldsymbol{j}) \\\boldsymbol{T}'=-2\cdot(\sin \left(2t\right)\boldsymbol{i}+\cos \left(2t\right)\boldsymbol{j})$